On a sightseeing trip to Paris, Betty spots the spire of a cathedral at 22 degrees and Cathy spots the same spire at 30 degrees.
1 answer:
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Answer:
The last choice is the one you want
Step-by-step explanation:
First of all, a parabola has a minimum value if it is a positive parabola, one that opens upward. The first and the third parabolas are negative so they open upside down. That leaves us with choices 2 and 4. We find the side to side and up or down movement by finishing the completion of the square that has already been started for us. Do this by factoring what's inside the parenthesis into a perfect square binomial.
The second one factored becomes:
which reflects a shift to the right 3 and up 1. Not what we are asked to find.
The fourth one factored becomes:
which reflects a shift to the right 3 and down 5. That's what we want!
Answer:
the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251
Option A) is the correct answer.
Step-by-step explanation:
Given the data in the question;
we know that a type 11 error occur when a null hypothesis is false and we fail to reject it.
as in it in the question;
obtained mean is 9.8 which is obviously not equal to 8.3
But still we fail to reject the null hypothesis says mean is 8.3
Hence we have to find the probability of type 11 error
given that; it is right tailed and o.5, it corresponds to 1.645
so
z is equal to 1.645
z = (x-μ)/
where our standard deviation s = 3.8
sample size n = 50
mean μ = 8.3
we substitute
1.645 = (x - 8.3)/
1.645 = (x - 8.3) / 0.5374
0.884023 = x - 8.3
x = 0.884023 + 8.3
x = 9.18402
so, by general rule we will fail to reject the null hypothesis when we will get the z value less than 1.645
As we reject the null hypothesis for right tailed test when the obtained test statistics is greater than the critical value
so, we will fail to reject the null hypothesis as long as we get the sample mean less than 9.18402
Now, for mean 9.8 and standard deviation 3.8 and sample size 50
Z = (9.18402 - 9.8)/
Z = -0.61598 / 0.5374
Z = - 1.1462 ≈ - 1.15
from the z-score table;
P(z<-1.15) = 0.1251
Therefore, the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251
Option A) is the correct answer.