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QveST [7]
3 years ago
15

On a sightseeing trip to Paris, Betty spots the spire of a cathedral at 22 degrees and Cathy spots the same spire at 30 degrees.

If the two girls are 310 feet apart, determine the height of the spire (to the nearest foot).
Mathematics
1 answer:
jonny [76]3 years ago
7 0

Answer:

The height of the spire is 74 feet.

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3 0
2 years ago
A student desired to invest $1,540 into an investment at 9% compounded semiannually for 6 years. With all else equal, what is th
irga5000 [103]

Answer:

The future value of this initial investment after the six year period is $2611.6552

Step-by-step explanation:

Consider the provided information.

A student desired to invest $1,540 into an investment at 9% compounded semiannually for 6 years.

Future value of an investment: FV=P(1+r)^n

Where Fv is the future value, p is the present value, r is the rate and n is the number of compounding periods.

9% compounded semiannually for 6 years.

Therefore, the value of r is: r=\frac{0.09}{2}=0.045

Number of periods are: 2 × 6 = 12

Now substitute the respective values in the above formula.

FV=1540(1+0.045)^{12}

FV=1540(1.045)^{12}

FV=1540(1.69588)

FV=2611.6552

Hence, the future value of this initial investment after the six year period is $2611.6552

6 0
3 years ago
Plz i NEED HELP ABOUT TO FINISH THIS CLASS! PLZ
GrogVix [38]
The last one quick quick
3 0
2 years ago
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Need this for my teacher
ra1l [238]
I believe you combine the first and last terms first because they have the same denominator
4 0
2 years ago
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in a standard casino dice game the roller wins on the first roll if he rolls a sum of 7 or 11. what is the probability of winnin
Alborosie

<u>Answer-</u>

<em>The probability of winning on the first roll is </em><em>0.22</em>

<u>Solution-</u>

As in the game of casino, two dice are rolled simultaneously.

So the sample space would be,

|S|=6^2=36

Let E be the event such that the sum of two numbers are 7, so

E = {(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}

|E|=56

\therefore P(E)=\dfrac{|E|}{|S|}=\dfrac{6}{36}

Let F be the event such that the sum of two numbers are 11, so

F = {(6,5), (5,6)}

|F|=2

\therefore P(F)=\dfrac{|F|}{|S|}=\dfrac{2}{36}

Now,

P(\text{sum is 7 or 11)}=P(E\ \cup\ F)=P(E)+P(F)=\dfrac{6}{36}+\dfrac{2}{36}=\dfrac{8}{36}=\dfrac{2}{9}=0.22

8 0
3 years ago
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