The solution for the inequalities 3y>2x+12, 2x+y<=-5 is the value of x<-27/8 and y<7/4.
Given 3y>2x+12 and 2x+y<=-5.
We are given two inequalities 3y>2x+12 and 2x+y<=-5. Inequality are like equations but in greater than ,less than or in combination with equal to. To solve them we need to first write them properly.
2x-3y<-12
2x+y<=-5
Now assume these are equalities
2x-3y=-12
2x+y=-5
now subtract 2 from 1
2x-3y-2x-y=-12+5
-4y=-7
y=7/4
put the value of y in 2x-3y=-12
2x-3(7/4)=-12
2x-21/4=-12
2x=-12+21/4
2x=(-48+21)/4
2x=-27/4
x=-27/8
Now put the signs between the values
x<-27/8
y<7/4.
Hence the solution of the inequalities 3y > 2x + 12
2x + y ≤ -5 is the value of x<-27/8 and y<7/4.
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N+(n+1)= 57
Combine like terms
2n+1=57
Subtract 1 from both sides
2n=56
Divide both sides by 2
n=28
Final answer: 28, 29
Answer:
1 1/3
Step-by-step explanation:
1/3+1/3+1/3+1/3 is 1 and 1/3 cups
If 15% of the number was 9, i would divide it by fifteen and multiply by 100. Doviding by fifteen would get 1%, which in this case is 0.6. Then multiplying it by 100 would gove you 100%, or the whole number. The answer would be 60.
Answer:
Step-by-step explanation:
-18 = p / 2....multiply both sides by 2, cancelling out the 2 on the right side
-18 * 2 = p
- 36 = p <===
if it makes it easier to understand, p/2 is the same as (1/2)p