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3 years ago

5. Jaeden is shopping for shoes. The available styles are Jordan (J), Adidas (A), and Under Armor

Mathematics

1 answer:

Naddika [18.5K]3 years ago

3 0

Answer:

AU UA?

Step-by-step explanation:

I hope this helps:)

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Does the inequality sing mean equals in an equasion

shtirl [24]

Here are the 4 inequality signs.

$a < b$ ---> a is less than b
$a \le b$ ---> a is less than or equal to b
$a > b$ ---> a is greater than b
$a \ge b$ ---> a is greater than or equal to b

For the second and fourth lines above, the two sides may or may not be equal.
For the first and third lines above, the two sides cannot be equal.

6 0

3 years ago

Find all possible values of α+

const2013 [10]

Answer:

$\rm\displaystyle 0,\pm\pi$

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma )$

factor out tanγ:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)$

divide both sides by tanαtanβ-1 and that yields:

$\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}$

multiply both numerator and denominator by-1 which yields:

$\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)$

recall angle sum indentity of tan:

$\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta )$

let α+β be t and transform:

$\rm\displaystyle \tan( \gamma ) = - \tan( t)$

remember that tan(t)=tan(t±kπ) so

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi )$

therefore when k is 1 we obtain:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi )$

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi )$

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

$\rm\displaystyle \gamma = - \alpha - \beta \pm \pi$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }$

when is 0:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta \pm 0 )$

likewise by Opposite Angle Identity we obtain:

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 )$

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

$\rm\displaystyle \gamma = - \alpha - \beta \pm 0$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }$

and we're done!

8 0

3 years ago

Read 2 more answers

PlSSS HELP IF YOU TURLY KNOW THISS

o-na [289]

Answer:

x=3 hope this helps

Step-by-step explanation:

8 0

3 years ago

What is the set of all solutions to the equation \sqrt{x + 2}= {-x} x+2 =−xsquare root of, x, plus, 2, end square root, equals

NARA [144]

Answer:

$x = 2$ or $x = -1$

Step-by-step explanation:

Given

$\sqrt{x + 2}= {-x}$

Required

Find the possible values fo x

$\sqrt{x + 2}= {-x}$

Square both sides

$( \sqrt{x + 2})^2= ({-x})^2$

$x + 2 = x^2$

Equate to 0

$x^2 - x - 2 = 0$

Expand

$x^2 + x -2x - 2 = 0$

Factorize:

$x(x + 1) - 2(x + 1) = 0$

$(x -2)(x +1) = 0$

Split:

$x - 2 = 0$ or $x + 1 = 0$

$x = 2 + 0$ or $x = 0-1$

$x = 2$ or $x = -1$

3 0

3 years ago

Help me with this!!!

geniusboy [140]

Answer:

-7

Step-by-step explanation:

4 0

3 years ago