Why did the cow keep jumping over the barrel

What is the value of x for which m || n?<br> x = 40<br> x = 5<br> x = 105<br> x = 30

QveST [7]

Answer:

(A) x=40

Step-by-step explanation:

Given: It is given that m is parallel to n.

To find: The value of x.

Proof: It is given that m is parallel to n, from the figure it can be seen that 105° and (3x-15)° forms alternate exterior angles which are equal in measure because m is parallel to n.

Thus, $105^{\circ}=3x-15^{\circ}$

⇒ $105^{\circ}+15^{\circ}=3x$

⇒ $120^{\circ}=3x$

⇒ $\frac{120}{3}=x$

⇒ $x=40$

Thus, the value of x is 40, hence option A is correct.

4 0

3 years ago

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A car dealership sells 0, 1, or 2 luxury cars on any day. When selling a car, the dealer also tries to persuade the customer to

melisa1 [442]

Answer:

Mean = 1.42

Variance = 0.58

Step-by-step explanation:

Given: X denote the number of luxury cars sold in a given day, and Y denote the number of extended warranties sold.

Also, joint probability function of X and Y are given.

To find:

mean and variance of X

Solution:

From the given joint probability function of X and Y,

$P(X=0)=\frac{1}{6}\\P(X=1)=\frac{1}{12}+\frac{1}{6}=\frac{1+2}{12}=\frac{3}{12}\\P(X=2)=\frac{1}{12}+\frac{1}{3}+\frac{1}{6}=\frac{1+4+2}{12}=\frac{7}{12}$

Mean of X:

$E(X)=\sum XP(X)\\=0\left ( \frac{1}{6} \right )+1\left ( \frac{3}{12} \right )+2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{14}{12}\\=\frac{17}{12}=1.42$

Variance of X:

$E(X^2)=\sum X^2P(X)\\=0^2\left ( \frac{1}{6} \right )+1^2\left ( \frac{3}{12} \right )+2^2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{28}{12}\\=\frac{31}{12}$

$var(X)=E\left [ X^2 \right ]-\left ( E\left [ X \right ] \right )^2\\=\frac{31}{12}-\left ( \frac{17}{12} \right )^2\\=\frac{31}{12}-\frac{289}{144}\\=\frac{372-289}{144}\\=\frac{83}{144}\\=0.58$

5 0

4 years ago

After being rearranged and simplified, which of the following equations could

masha68 [24]

Answer:

C and D

Step-by-step explanation:

The quadratic formula is

x= (-b±√b²-4ac)/2a

The formula uses the numerical coefficients in the quadratic equation.

The general quadratic equation is ax²+bx+c where a, b and c are the numerical coefficients

So, lets try and see;

A.

$5x+4=3x^4-2\\\\=3x^4-5x-2-4\\=3x^4-5x-6\\a=3,b=-5,c=-6$

But due to the fact that in this equation you have x⁴, the equation is not a quadratic equation thus can not be solved using this formula

B

$-x^2+4x+7=-x^2-9\\\\\\=-x^2+x^2+4x+7+9\\=4x+16$

C

$9x+3x^2=14+x-1\\\\\\=3x^2+9x-x-14+1\\\\=3x^2+8x-13\\\\\\a=3,b=8,c=-13\\$

D.

$2x^2+x^2+x=30\\\\\\=3x^2+x-30\\\\\\a=3,b=1,c=-30$

From the checking above, the equations will be C and D

7 0

3 years ago

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What best describes movement of particles in a solid

Fudgin [204]

Answer:The particles in a solid are tightly packed and locked in place. Although we cannot see it or feel it, the particles are moving = vibrating in place.

7 0

3 years ago

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Melissa buys 2 1/2 pounds of salmon and 1 1/4 pounds of swordfish. She pays a total of $31.25, and the swordfish cost $.20 per p

julsineya [31]

Answer:

The combined cost of 1 pound of salmon and 1 pound of swordfish is $16.66

Step-by-step explanation:

Let us assume the cost of 1 pound salmon = $ m

So the cost of 1 pound of 1 pound swordfish cat = $ ( m - 0.20)

Now, the Amount of salmon purchased = 2 1/2 pounds

$2\frac{1}{2} = 2 + \frac{1}{2} = 2 + 0.5 = 2.5$

So, the amount of salmon purchased = 2.5 pounds

Cost of buying 2.5 pounds = 2.5 x ( 1 pound cost)

= 2.5 ( m) = $ 2.5 m ...... (1)

Also, the Amount of swordfish purchased = 1 1/4 pounds

$1\frac{1}{4} = 1 + \frac{1}{4} = 1 + 0.25 = 1.25$

So, the amount of swordfish purchased = 1.25 pounds

Cost of buying 1.25 pounds = 1.25 x ( 1 pound cost of swordfish)

= 1.25 ( m - 0.20) = $ 1.25 m - 0.25 .... (2)

Now, the combined cost paid = $ 31.25

⇒Cost of buying (2.5 pounds salmon + 1.25 pounds swordfish) = $ 31.25

or, 2.5 m + 1.25 m - 0.25 = 31.35 (from (1) and (2))

or, 3.75 m = 31.60

or, m = 31.60/3.75 = 8.43

⇒ m = $8.43

So, the cost of 1 pound salmon = m = $8.43

and the cost of 1 pound swordfish = m - 0.20 = $8.43 - 0.20 = $ 8.23

Hence, the combined cost 1 pound of salmon and 1 pound of swordfish = $8.43 + $ 8.23 = $ 16.66

6 0

4 years ago