So since they are similar
AC/BC=CD/CE
so
(66-x)/30=(x+4)/5
times both sides by 5
(66-x)/6=x+4
times both sides by 6
66-x=6(x+4)
distribute
66-x=6x+24
add x to both sides
66=7x+24
minus 24 from both sides
42=7x
divide both sides by 7
6=x
x=6 units
if its diameter is 14, then its radius is half that or 7.
![\textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=7 \end{cases}\implies \begin{array}{llll} V=\cfrac{4\pi (7)^3}{3}\implies V=\cfrac{1372\pi }{3} \\\\\\ \stackrel{using~\pi =3.14}{V\approx 1436.03} \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Bvolume%20of%20a%20sphere%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B4%5Cpi%20r%5E3%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D7%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20V%3D%5Ccfrac%7B4%5Cpi%20%287%29%5E3%7D%7B3%7D%5Cimplies%20V%3D%5Ccfrac%7B1372%5Cpi%20%7D%7B3%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7Busing~%5Cpi%20%3D3.14%7D%7BV%5Capprox%201436.03%7D%20%5Cend%7Barray%7D)
Answer:
a)
Let x = number of candy bars sold
Let y = amount of money earned
b)
y = 0.75x
c)
He should work at the car wash.
Step-by-step explanation:
a)
Let x = number of candy bars sold
Let y = amount of money earned
b)
$42.75/57 = $0.75
Each candy bar costs $0.75
We can confirm that by dividing $38.25/51 = $0.75
1 candy bar sells for $0.75
2 candy bars sell for $0.75 * 2
x candy bars sell for 0.75 * x, or simply 0.75x
The equation is y = 0.75x
c)
y = 0.75x
y = 0.75 * 36
y = 27
Larry raised $27 by selling candy bars last year. This year, he can earn more than that by working at the car wash.
He should work at the car wash.
Answer:
x² + 10x - 24
Step-by-step explanation:
3x² - 12 + (x - 4)(2 - x) - (x² - 4x + 4)
= 3x² - 12 + (2x - x² - 8 + 4x) - x² + 4x - 4
= 3x² - 12 + 2x - x² - 8 + 4x - x² + 4x - 4
= x² + 10x - 24
The answer is 106.5 by using sin(28) = 50/x
