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Otrada [13]
3 years ago
8

Volume is expressed in

Mathematics
1 answer:
statuscvo [17]3 years ago
7 0

Answer:

Cubic Units

Step-by-step explanation:

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Which region contains the solution
dangina [55]
Hello!

In this case, there are no solutions because the lines are parallel, and the system of inequalities are opposite each other. 


Hope this helps :))
5 0
3 years ago
Read 2 more answers
Answer pleaseeeee 15 pts
Nataly_w [17]

Answer:

E

Step-by-step explanation:

89 + 95 = 184

89 x 15% increases the number of boys by 13             89 + 13 = 102

95 x 20% decreases the girls by 19                              95 -  19 =  76

                                                                               102 + 76 + 178

6 0
3 years ago
Solve the equations below for x. Please show your math work step by step.
strojnjashka [21]

Answer:

x = 14 and x = - 7

Step-by-step explanation:

Not that + (- ) = -

(a)

x + (- 4) = 10, that is

x - 4 = 10 ( add 4 to both sides )

x = 14

(b)

2x - 10 = - 24 ( add 10 to both sides )

2x = - 14 ( divide both sides by 2 )

x = - 7

8 0
3 years ago
What is x? I have been having trouble with these
Wittaler [7]

Answer:

x=4

Step-by-step explanation:

(whole secant) x (external part) =   (whole secant) x (external part)

(6+x) * 6 =(5+x+3) *5

(6+x) * 6 =(x+8) *5

Distribute

36+6x = 5x+40

Subtract 5x from each side

36+6x-5x = 5x-5x+40

36+x = 40

Subtract 36 from each side

36+x-36 = 40-36

x = 4

3 0
3 years ago
The average of six positive integers starting with a is equal to b. What is the average of five consecutive integers ending with
kvasek [131]

The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.

<h3>What is the average of five consecutive integers ending with b?</h3>

First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;

(a+a+2+a+4+a+6+a+8+a+10)/6 = b

6b=6a+30

b=a+5

Also, let the average of the consecutive intergers ending with b be denoted by; x.

(b+b-1+b-2+b-3+b-4)/5 = x

=(5b-10)/5

=b–2

The average, x=b – 2 (where b = a-5)

Ultimately, the value of the required average is; = a+5-2 = a+3.

Read more on average of integers;

brainly.com/question/24369824

#SPJ1

7 0
1 year ago
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