Volume is expressed in

What is the other zero of the quadratic function?

svetoff [14.1K]

Answer:

he zeros of a quadratic equation are the points where the graph of the quadratic equation crosses the x-axis.

Step-by-step explanation:

3 0

3 years ago

How many feet and inches in 62 inches?

Agata [3.3K]

There are 5 feet and 2 inches in 62 inches. Hope this helps!

3 0

3 years ago

Read 2 more answers

Can any on help on 4-6 only please it would be grateful

Inessa05 [86]

Answer:

4. h=9in

5. 150.8 $m^{2}$

6. 301.6 $in^{2}$

Step-by-step explanation:

4.

Surface area of a rectangular prism form : A=2(wl+hl+hw)

Substitute in values from the question: 558=2[(9)(11)+h(11)+h(9)]

Multiply where applicable: 558=2[(99)+11h+9h]

Combine like terms: 558=2[(99)+20h]

Divide both sides by 2: 279=(99)+20h

*note- This step can also be seen as multiplying the right side by 2 without messing with the left at all (558=(198)+40h) then you would solve in the same fashion as I will from here just with the alternative numbering*

Subtract to isolate the h: 180=20h

Divide both sides to isolate the h: 9=h

Now we see that the missing dimension h=9in

*note- I did not bold the equations with squares so please don't be confused by that*

5.

Surface area of a cylinder form: A=2πrh+2π $r^{2}$

Substitute in values from the question: A=2π(3)(5)+2π $3^{2}$

Multiply were applicable: A≈94.2+56.5

Add remaining values: A≈150.8

Now we see that the total surface area is 150.8 $m^{2}$

*note- whenever we solve for volume or SA of a figure we square the unit ( $m$ ➞ $m^{2}$ )*

6.

Surface area of a cylinder form: A=2πrh+2π $r^{2}$

Substitute in values from the question: A=2π(6)(2)+2π $6^{2}$

*note- we use 6 instead of the given value 12 because the equation calls for the radius and not the diameter*

Multiply were applicable: A≈75.2+226.2

Add remaining values: A≈301.6

Now we see that the total surface area is 301.6 $in^{2}$

*note- whenever we solve for volume or SA of a figure we square the unit ( $in$ ➞ $in^{2}$ )*

Hope this helps :)

4 0

3 years ago

Nina has prepared the following two-column proof below. She is given that ∠OLN ≅ ∠LNO and she is trying to prove that OL ≅ ON. S

Anit [1.1K]

Step number 3 should really be step number 7, it should be placed after step 4, 5, and 6. The reason is because we won't know that ∠LEO ≅ ∠NEO until after we learn that LE ≅ EN. Because of this, step 3 is in the wrong spot (mistake number one). The secod mistake is that step 7, triangle OLE ≅ triangle ONE is congruent by Angle-Side-Angle (ASA) Postulate, not Side-Angle-Side (SAS) Postulate. It is congruent by ASA because we know that both triangles have equal angles N and L. We also know that the perpendicular bisector creates a 90° angle. So m∠LEO = 90° and ∠NEO = 90°. Therefore, we already have 2 congruent angles in both of the triangles. We also learn that line LE ≅ EN based on the definition of a perpendicular bisector, so we have know one that one side of each triangle is congruent. It is ASA and not AAS, because the ASA Postulate states that two angles and one included side of one triangle are congruent to two angles and one included side of another triangle.

7 0

3 years ago

The total score in a football game was 31 points.

Alisiya [41]

Answer:

25

Step-by-step explanation:

First we need to create an equation. We’ll say the losing team scored x points. If the winning team scored 19 more, they would have x + 19 points. We know the total is 31 points, so we end up with x + x + 19 = 31, or 2x + 19 = 31. Subtract 19 from both sides to get 2x = 12. Divide both sides by 2, and get x = 6. To find out how much the winning team scored, which we know is x + 19, put 6 in for x and get 25.

6 0

2 years ago