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ryzh [129]
3 years ago
14

What is the answer to the equation 4x-5.6=8x+5

Mathematics
1 answer:
Natasha2012 [34]3 years ago
8 0
X=−2.65 is the answer.
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question; The chart below shows the number of tickets to the annual teachers vs. students basketball game. What was the most num
katen-ka-za [31]

Answer:

60

Step-by-step explanation:

The most amount of tickets sold is 60 tickets, as it shows on the graph.

4 0
2 years ago
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Which equation is equivalent to 2x + 6y = 12?
mixer [17]

Answer:

Option C, y = -1/3x + 2

Step-by-step explanation:

2x + 6y = 12

<u>Step 1:  Solve for y</u>

2x + 6y - 2x = 12 - 2x

6y / 6 = (12 - 2x) / 6

y = 2 - 1/3x

Answer:  Option C, y = -1/3x + 2

6 0
3 years ago
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Hector is competing in a 42-mile bicycle race. He has
m_a_m_a [10]

Answer:

Let x = the hours needed for Wanda to catch up to Hector.

Hector has already completed 18 miles. Hector travels at 12 miles per hour.

After x more hours, Hector will travel

18 + 12x miles

Wanda travels at 16 miles per hour. In x hours, she travels

16x miles

If Wanda catches up to Hector, then

16x = 18 + 12x

4x = 18

x = 4.5 hours

Answer:  4 hours, 30 minutes (or 4.5 hours)

Step-by-step explanation:

7 0
2 years ago
Simplify the radical completely.
AlladinOne [14]

Answer:

D

Step-by-step explanation:

\sqrt{300}  =  \sqrt{100 \times 3}  =  \sqrt{100}  \times  \sqrt{3}  = 10 \sqrt{3}

3 0
2 years ago
A circular cake with a radius of 8 inches is cut from the center into 6 equal pieces. How many inches wide, to the nearest tenth
aalyn [17]

Answer: 8.4 inches.

Step-by-step explanation:

We know that the circumference of a circle can be calculated with this formula:

C=2\pi r

Where "r" is the radius of the circle.

We know that the circular cake (whose radius is 8 inches) is cut from the center into 6 equal pieces. Then, you need to divide the circumference of this circular cake by 6 to find the width of the outer edge of each piece of cake.

Therefore, this is (to the nearest tenth of an inch):

C=\frac{2\pi (8in)}{6}\\\\C=8.4in

5 0
3 years ago
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