So lets try to prove it,
So let's consider the function f(x) = x^2.
Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).
Using the Intermediate Value Theorem,
it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.
Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.
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Answer:
x = 32°
Step-by-step explanation:
∆KLM is an isosceles triangle because it has two equal sides, KL & KM. Therefore, the angles opposite to each of the two equal sides, which are referred to as the base angles are congruent to each other.
m<KML = m<KLM = 58°
m<MKL = 180 - (58 + 58) (Sum of triangle)
m<MKL = 64°
m<JKM = 180 - m<MKL (linear pair theorem)
m<JKM = 180 - 64 (Substitution)
m<JKM = 116°
∆JKM is also an isosceles triangle with two equal sides. Therefore, it's based angles (x & <J) would also be equal to each other.
Thus:
x = ½(180 - m<JKM)
x = ½(180 - 116) (Substitution)
x = 32°
Answer:
11 cm
Step-by-step explanation:
16-5 = 11
The forth picture is the one that represents 4.5
Using the given linear function of best-fit, the most likely approximate height of the plant after 8 weeks would be of 7.4 centimeters.
<h3>What is a linear function?</h3>
A linear function is modeled by:
y = mx + b
In which:
- m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
- b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.
The line of best-fit goes through points (0,1) and (5,5). Point (0,1) means that the y-intercept is of b = 1. The slope is given as follows:
m = (5 - 1)/(5 - 0) = 4/5 = 0.8.
Hence the equation that gives the approximate height after x weeks is:
y = 0.8x + 1.
After 8 weeks, the expected height is:
y = 0.8 x 8 + 1 = 6.4 + 1 = 7.4 centimeters.
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