Account A
A=p+i
A=25,000+(925×5)
A=29,625
Account B
A=p(1+rt)
A=25,000×(1+0.065×5)
A=33,125
How much more did the account B earn
33,125−29,625
=3,500
Given:
The width of a rectangle is x centimeters and its length is (x+ 2) cm.
To find:
The expression for the perimeter of the rectangle.
Solution:
We know that, perimeter of a rectangle is

We have,
Width = x cm
Length = (x+2) cm
Putting these values in the above formula, we get




Therefore, the required expression for the perimeter of the rectangle is (4x+4) cm.
Answer:
1.# = 119.2 2.# = 869.545454545 3.# = 443.66666666 4.# = 13501.3939394
Step-by-step explanation:
i don't know about the 2 one and 3 and 4 one that came up a very big number. I used a calculator though.exactly way you tired to tipe it in sorry it took so long to answer the problem!!!.
The points you found are the vertices of the feasible region. I agree with the first three points you got. However, the last point should be (25/11, 35/11). This point is at the of the intersection of the two lines 8x-y = 15 and 3x+y = 10
So the four vertex points are:
(1,9)
(1,7)
(3,9)
(25/11, 35/11)
Plug each of those points, one at a time, into the objective function z = 7x+2y. The goal is to find the largest value of z
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Plug in (x,y) = (1,9)
z = 7x+2y
z = 7(1)+2(9)
z = 7+18
z = 25
We'll use this value later.
So let's call it A. Let A = 25
Plug in (x,y) = (1,7)
z = 7x+2y
z = 7(1)+2(7)
z = 7+14
z = 21
Call this value B = 21 so we can refer to it later
Plug in (x,y) = (3,9)
z = 7x+2y
z = 7(3)+2(9)
z = 21+18
z = 39
Let C = 39 so we can use it later
Finally, plug in (x,y) = (25/11, 35/11)
z = 7x+2y
z = 7(25/11)+2(35/11)
z = 175/11 + 70/11
z = 245/11
z = 22.2727 which is approximate
Let D = 22.2727
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In summary, we found
A = 25
B = 21
C = 39
D = 22.2727
The value C = 39 is the largest of the four results. This value corresponded to (x,y) = (3,9)
Therefore the max value of z is z = 39 and it happens when (x,y) = (3,9)
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Final Answer: 39
7x + 15 = 1520
It’s $7 times the unknown number of shirts (x). Plus $15 to ship. All has to equal the total of $1,520.