Answer:
$1452
Step-by-step explanation:
The answer is B. Thank me in the future!
always remember ~Positive Vibes~
{tan(60) + tan(10)}/{1 - tan(60)*tan(10)} - {tan(60) - tan(10)}/{1 + tan(10)*tan(60)}
<span>ii) Taking LCM & simplifying with applying tan(60) = √3, the above simplifies to: </span>
<span>= 8*tan(10)/{1 - 3*tan²(10)} </span>
<span>iii) So tan(70) - tan(50) + tan(10) = 8*tan(10)/{1 - 3*tan²(10)} + tan(10) </span>
<span>= [8*tan(10) + tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} </span>
<span>= [9*tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} </span>
<span>= 3 [3*tan(10) - tan³(10)]/{1 - 3*tan²(10)} </span>
<span>= 3*tan(30) = 3*(1/√3) = √3 [Proved] </span>
<span>[Since tan(3A) = {3*tan(A) - tan³(A)}/{1 - 3*tan²(A)}, </span>
<span>{3*tan(10) - tan³(10)}/{1 - 3*tan²(10)} = tan(3*10) = tan(30)]</span>
Answer:
<h2><u><em>
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Step-by-step explanation:
● A standard deck of cards has:
● 52 Cards in 13 values and 4 suits
● Suits are Spades, Clubs, Diamonds
and Hearts
● Each suit has 13 card values:
2-10, 3 “face cards” Jack, Queen, King (J, Q, K)
and and Ace (A)
Basic Card Probabilities
● If you draw a card at random, what is the
probability you get:
● A Spade? P(Spade)=13/52
● A Face card? P(Face Card)=12/52 (or simply 3/13)
● A Red Ace? P(Red Ace) = 2/52
