The plotted point will be reflected across the y-axis.
First thing to do is to illustrate the problem, Since it was mentioned that work was along the way to training, the order is shown in the picture. Mary's home and workplace are nearer compared to her training center. It is also mentioned that the distance between work and home, denoted as x, is 2/3 of the total distance from home to training. The total distance is (x + 2.5). Thus,
x = 2/3(x+2.5)
x = 2/3 x + 5/3
1/3 x = 5/3
x = 5 km
Thus, the distance from home to work is 5 km. This means that Mary has to walk this distance twice to return home to get her shoes. Then, she will travel again the total distance of 5+2.5 = 7.5 km to get to her training center. So,
Total distance = 2(5km) + 7.5 km
Total distance = 17.5 km
Answer:
The 16 cans for 13.60
Step-by-step explanation:
21.36 ÷ 24 = 0.89
10.56 ÷ 12 = 0.88
17.20 ÷ 20 = 0.86
13.60 ÷ 16 = 0.85
The 16 cans for 13.60 is the best buy, just remember, cost ÷ amount!!
Answer:
m∠P = 70°, m∠T = 20°, m∠SKP = 40° , and m∠MKT = 70°
Step-by-step explanation:
* Lets explain how to solve the problem
- In Δ PST
∵ m∠S = 90°
∴ m∠T + m∠P = 90° ⇒ interior angles of a triangle
∵ m∠SPK/m∠KPT = 5/2
- The ratio between the two angles are 5 : 2 , multiply the parts of the
ratio by x, where x is a real number
∴ m∠SPK = 5x
∴ m∠KPT = 2x
∵ m∠SPK + m∠KPT = m∠P
∴ m∠P = 5x + 2x = 7x
- In ΔPKT
∵ KM ⊥ PT
∵ MP = Mt
∴ KM is perpendicular bisector of PT
∴ ΔPKT is an isosceles triangle with KP = KT
∵ KP = KT
∴ m∠KPT = m∠T
∵ m∠KPT = 2x
∴ m∠T = 2x
∵ m∠T + m∠P = 90°
∵ m∠P = 7x
∵ m∠T = 2x
∴ 2x + 7x = 90 ⇒ solve for x
∴ 9x = 90 ⇒ divide both sides by 9
∴ x = 10
∵ m∠P = 7x
∴ m∠P = 7(10) = 70°
∴ m∠P = 70°
∵ m∠T = 2x
∴ m∠T = 2(10) = 20°
∴ m∠T = 20°
- In ΔSKP
∵ m∠S = 90°
∵ m∠SPK = 5x = 5(10) = 50°
∴ m∠SKP = 180° - (90° + 50°) = 180° - 140° = 40° ⇒ interior angles of a Δ
∴ m∠SKP = 40°
- In Δ KMT
∵ m∠KMT = 90°
∵ m∠T = 20°
∴ m∠MKT = 180° - (90° + 20°) = 180° - 110° = 70° ⇒ interior angles of a Δ
∴ m∠MKT = 70°