Question

Can anyone help me out on finding the solutions to this problem?

Answer 1

Solve:

sqrt 6x^2 + 2x - sqrt 3 / 2 = 0 ====> Answer - sqrt 3 / 2, sqrt 6 / 6

- 2 +/- sqrt 4 + 4 sqrt 6 * sqrt 3/2 / 2 sqrt 6

- 2 +/- sqrt 4 + 12 / 2 sqrt 6

- 2 +/- 4 / 2 sqrt 6

- 6 / 2 sqrt 6 or - 2 / 2 sqrt 6

- 3 / sqrt 6 or 1 / sqrt 6

- 3 sqrt 6 / 6

Decimals: x = 0.40825, Decimal: x = - 1.22474

Answer ==========> - sqrt 3 / 2, sqrt 6 / 6

Hope that helps!!!! : )