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Travka [436]
3 years ago
10

$35 sweatshirt had a 26% markdown. What is the new price?

Mathematics
1 answer:
Katena32 [7]3 years ago
6 0

the new price will be 26.64. i hope this helps!!

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PLEASE HELP! I will give you the brainiest and A LOT of points! (Ch.5.7)
STALIN [3.7K]
Company A pays $5500 more than B in year 10

4 0
2 years ago
If you guys can answer this then please help
s344n2d4d5 [400]

Answer:

64°

Step-by-step explanation:

First, we have to find the angle situated in R, the addition of all angles in a triangle is 180° so that means:

x + 68 + 48 = 180

x = 180-116 = 64°

Now, remember that this angle (64°) is the same as this one = ?, thanks to one property.

So basically, that angle has the same value as that one.

? = 64°

Hope it was helpful ;)

8 0
3 years ago
a record store is having a sale during which all items will be sold at 25% less then marked prices. How much will a CD marked $1
BARSIC [14]

Answer:

$12

Step-by-step explanation:

If you're taking off 25% of the regular cost, "taking off" means subtracting.  So if we subtract 25% OF 16, the word "of" means to multiply here.  So our expression then becomes:

16 - .25(16)

16 - 4 = 12

So the CD will sell for $12.

4 0
3 years ago
Help with this question !
dem82 [27]
Liz runs the fastest
8 0
3 years ago
Read 2 more answers
The savings account offering which of these APRs and compounding periods offers the best APY?
zzz [600]
\bf \qquad  \qquad  \textit{Annual Yield Formula}
\\\\
~~~~~~~~~~~~\textit{4.0784\% compounded monthly}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0784\%\to \frac{4.0784}{100}\to &0.040784\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12
\end{cases}
\\\\\\
\left(1+\frac{0.040784}{12}\right)^{12}-1\\\\
-------------------------------\\\\
~~~~~~~~~~~~\textit{4.0798\% compounded semiannually}\\\\


\bf ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0798\%\to \frac{4.0798}{100}\to &0.040798\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2
\end{cases}
\\\\\\
\left(1+\frac{0.040798}{2}\right)^{2}-1\\\\
-------------------------------\\\\


\bf ~~~~~~~~~~~~\textit{4.0730\% compounded daily}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0730\%\to \frac{4.0730}{100}\to &0.040730\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{daily, thus 365}
\end{array}\to &365
\end{cases}
\\\\\\
\left(1+\frac{0.040730}{365}\right)^{365}-1
7 0
3 years ago
Read 2 more answers
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