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grandymaker [24]

3 years ago

7

Please can someone help I try it hard but I don’t understand it

2 answers:

sammy [17]3 years ago

5 0

He could have scored 7, 14, 21, 28, 35, or 42 points (all multiples of 7 less than 45).

answer: B

vladimir2022 [97]3 years ago

4 0

The answer would be 35!

The reason that this would be the answer is because of all the given answers only two of them are a multiple of 7, which are 79 and 35.

Out of both of these possibilities only one of them is lower than 45, which is 35. That’s how you get the answer! :)

You might be interested in

Which shows the best estimate to use<br> to find 43 × 78?

bulgar [2K]

Answer:

The best estimate for 43x78 is 40x80

Step-by-step explanation:

43 rounded to the nearest ten is 40.

78 rounded to the nearest ten is 80.

The answer to 40x80 is 3200

7 0

3 years ago

Olivia is thinking of a number.She says, "My number is odd. It is a factor of 30 and a multiple of 3"

Katarina [22]

Answer:

15

Step-by-step explanation:

Factors of 30:

1 , 2, 3, 5, 6, 10, 15, 30

Multiples of 3:

3, 6, 9, 12, 15, etc.

The first number (and only number) shared by both sets is 15, therefore 15 is your answer.

~

8 0

3 years ago

Read 2 more answers

You like math then here

Igoryamba

Answer:

-8b + 9 - 5k

Step-by-step explanation:

I am assuming the blue highlighted portion is your answer, and is not a part of the initial question

(-4b + 15 - 7k) - (6 + 4b - 2k)

Combine like terms

-4b - + 4b

Negative + Positive = Negative

-4b - 4b = -8b

15 - 6 = 9

-7k - - 2k

Negative + Negative = Positive

-7k + 2k = -5k

Put them all together:

0b + 9 - 5k

Simplify

-8b + 9 - 5k

I got the same answer as you (just in a different order)

5 0

2 years ago

<img src="https://tex.z-dn.net/?f=4%5E%7B2%7D" id="TexFormula1" title="4^{2}" alt="4^{2}" align="absmiddle" class="latex-formula

Komok [63]

Step-by-step explanation:

step 1. what is 4^2?

step 2. 16.

3 0

3 years ago

Suppose r(t)=costi+sintj+3tk represents the position of a particle on a helix, where z is the height of the particle above the g

Ilia_Sergeevich [38]

a. The $\vec k$ component tells you the particle's height:

$3t=16\implies t=\dfrac{16}3$

b. The particle's velocity is obtained by differentiating its position function:

$\vec v(t)=\dfrac{\mathrm d\vec r(t)}{\mathrm dt}=-\sin t\,\vec\imath+\cos t\,\vec\jmath+3\,\vec k$

so that its velocity at time $t=\frac{16}3$ is

$\vec v\left(\dfrac{16}3\right)=-\sin\dfrac{16}3\,\vec\imath+\cos\dfrac{16}3\,\vec\jmath+3\,\vec k$

c. The tangent to $\vec r(t)$ at $t=\frac{16}3$ is

$\vec T(t)=\vec r\left(\dfrac{16}3\right)+\vec v\left(\dfrac{16}3\right)t$

4 0

3 years ago