Explanation:
Cell wall is not present in animal cells .
C precipitation because if you look at the diagram, you will see it is raining on the mountains.
The answer is that a unicellular organism would swell and burst.
In a hypotonic solution <span>the </span>water concentration<span> of the cell's cytoplasm is </span>lower<span> then that of the hypotonic solution. If unicellular organism is exposed to a hypotonic solution, the water from the solution will enter the organism by the process called osmosis. The aim is to balance water concentration on the inside and outside of the organism. But, that water entering the cytoplasm of the cell will make pressure on the cell membrane. If the </span><span>excess water cannot be removed from the organism, it will swell and burst.</span>
Answer:
C. An approximately three-to-one ratio of black to brown coated mice in F2 is accounted for by the black allele being dominant over the brown allele
Explanation:
Assuming the black genotype is BB and the brown genotype is bb.
At F1:
BB x bb = All Bb (black)
At F2:
Bb x Bb = BB (black), 2Bb (Black), bb (brown)
Th ratio of black to brown is 3:1
961 black : 317 brown is approximately 3:1.
Hence, the correct option is C.
<em>An approximately three-to-one ratio of black to brown coated mice in F2 is accounted for by the black allele being dominant over the brown allele</em>
Answer:
25% heterozygous tall
Explanation:
If we take the F1 generation as parents and let them self-fertilise, we have 4 crosses.
The first one for homozygous tall, then we have 100% AA.
The second and third one for heterozygous tall and we have 25% AA, 50%Aa and 25%aa for each of them.
The last one would be for dwarf, and we'll have 100%aa.
Adding all of them, we'll have
AA = 100 + 25 + 25 = 150%
Aa = 50+50 = 100%
aa = 100 + 25 + 25 = 150%
as we had 4 crosses, so dividing the total percentages by 4, we'll have,
AA = 37.5%
Aa = 25%
aa = 37.5%
:. The percentage of heterozygous tall would be 25%.
Hope it helps:)
