Answer:
In Explanation.
Step-by-step explanation:
In situations like this, you want to first find the equations of the individual lines.
Let's start with the left one.
It has a negative slope of 2 while it has a y-intercept of 1
y=-2x+1
is the equation.
The other line has a slope of 3/2.
The y-intercept is not visible, so we need to use point slope form.
I chose (2,-3)
y+3=3/2(x-2)
Simplify.
y=3x/2-3-3
y=3x/2-6
so we have
y=-2x+1
and
y=-6
Since both lines are solid, the signs are ≥ or ≤
The shadings intersect above both lines so the individual shadings also have to be above the line.
That means the equation is less than the "y".
y≥-2x+1
y≥-6
Hey! here is a trick for you
domain = all unique values of x
so, domain in the above relation is [0,1,4]
<span>it is a irrational number</span>
The y-intercept is where on the graph the line is intersecting the y=axis. Slope is in the form y=mx+b (b=y-intercept, mx=how far up and over.)
Expanded form:
1. 117.00= 100+ 10+ 7
2. 20.018 = 20+ 0.01+ 0.008
3. 13.265 = 10+ 3+ 0.2+ 0.06+ 0.005
4. 3.4000 = 3+ 0.4
5. 0.8100 = 0.8+ 0.01