Answer:
4
Step-by-step explanation:
6+10=16
2+2=4
16/4 = 4
Answer:
(3x+4)(5x+7)
Step-by-step explanation:
15x^2
+41x+28
Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2
+ax+bx+28. To find a and b, set up a system to be solved.
a+b=41
ab=15×28=420
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.
1,420
2,210
3,140
4,105
5,84
6,70
7,60
10,42
12,35
14,30
15,28
20,21
Calculate the sum for each pair.
1+420=421
2+210=212
3+140=143
4+105=109
5+84=89
6+70=76
7+60=67
10+42=52
12+35=47
14+30=44
15+28=43
20+21=41
The solution is the pair that gives sum 41.
a=20
b=21
Rewrite 15x^2
+41x+28 as (15x^2
+20x)+(21x+28).
(15x^2
+20x)+(21x+28)
Factor out 5x in the first and 7 in the second group.
5x(3x+4)+7(3x+4)
Factor out common term 3x+4 by using distributive property.
(3x+4)(5x+7)
Answer:
a. 4 : 1
b. 2 students
c. 3 : 1
Step-by-step explanation:
a. There were 12 students who got a C and 3 students who got As. The ratio is therefore:
12 : 3
Take it to the lowest form by dividing both sides by 3:
= 4 : 1
b. There were 4 students with a D grade and 8 with a B. The ratio is:
= 4 : 8
Taken to the lowest form that would be:
= 1 : 2
This means that for every student receiving a D, 2 students received an A.
c. 12 students received a C and 4 students received a D. That ratio is therefore:
= 12 : 4
Take to the lowest form by dividing both sides by 4:
= 3 : 1
Answer:
7*6-x
or
42-x
Step-by-step explanation:
decrease means subtraction,
product means multiplication
let x be the number you are decreasing by.
I am not really sure how to explain this, but here I go.
you take away x from the number that equals 6*7.
6*7 is 42 and you take away x from that, you get 42-x
or if you want to leave it unsimplified,
6*7-x
Answer:
Statements Reasons
1.
AB
bisects DAC 1. Given
A 2. 1 2 2. Defn Bisector
3. C and D are right angles 3. Given
A 4. C D 4. All Right ’s
S 5.
AB AB
5. Reflexive
6. ∆DAB ∆CAB 6. AAS
7.
BC BD
7. CPCTC
