Answer:
A, B, D
Step-by-step explanation:
A) y squared times y squared you just add the exponents
B) y^6/y^2 write it out as (y)(y)(y)(y)(y)(y)/(y)(y) then u cancel out two "y" from numerator and denominator and is left with y^4
C) is just 0 so its wrong
D) is the same process as B just cancel out 5 "y" from numerator and denominator and is left with y^4
E) is incorrect bc you need to add the exponents and you will get y^5 which is not equal to y^4 so yeah its wrong
7x - 1 = 20
7 times 3 is 21, 21 minus 1 is 20
Answer:
Base 5
Step-by-step explanation:
We want to determine the base at which:
113 X 2 =231
We consider the last number of the result (231).
The base must be a number such that:
3 X 2 will have a remainder of 1.
3 X 2 = 6 = 5 Remainder 1
Therefore:
113 X 2 =231 in positive integral number base 5.
Answer:
![f^{-1}(x)=\sqrt[3]{x}-1](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D-1)
Step-by-step explanation:
![f(x)=(x+1)^3\\\\y=(x+1)^3\\\\x=(y+1)^3\\\\\sqrt[3]{x}=y+1\\\\y=\sqrt[3]{x}-1\\ \\f^{-1}(x)=\sqrt[3]{x}-1](https://tex.z-dn.net/?f=f%28x%29%3D%28x%2B1%29%5E3%5C%5C%5C%5Cy%3D%28x%2B1%29%5E3%5C%5C%5C%5Cx%3D%28y%2B1%29%5E3%5C%5C%5C%5C%5Csqrt%5B3%5D%7Bx%7D%3Dy%2B1%5C%5C%5C%5Cy%3D%5Csqrt%5B3%5D%7Bx%7D-1%5C%5C%20%5C%5Cf%5E%7B-1%7D%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D-1)
Graphing both inverses, they will be symmetrical about the line 
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