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3 years ago

F(x) = x2+3x+2 x2+5x+4 Why is there no zero at x = –1?

1 answer:

7 0

You could rewrite $F(x)$ as

$\dfrac{x^2+3x+2}{x^2+5x+4}=\dfrac{(x+1)(x+2)}{(x+1)(x+4)}$

and be tempted to cancel out the factors of $x+1$ . But this cancellation is only valid when $x\neq-1$ .

When $x=-1$ , you end up with the indeterminate form $\dfrac00$ , which is why $-1$ is not a zero.

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Will mark 5 stars

lyudmila [28]

R is also known as the correlation coefficient. Hence your statement is ...
B. False

8 0

3 years ago

Which of the following statements are not true in developing a confidence interval for the population mean?

frutty [35]

Answer:

b) The width of the confidence interval becomes narrower when the sample mean increases.

Step-by-step explanation:

The confidence interval can be calculated as:

$\bar{x} \pm \text{Test Statistic}\displaystyle\frac{\sigma}{\sqrt{n}}$

a) The width of the confidence interval becomes wider as the confidence level increases.

The above statement is true as the confidence level increases the width increases as the absolute value of test statistic increases.

b) The width of the confidence interval becomes narrower when the sample mean increases.

The above statement is false. As the sample mean increases the width of the confidence interval increases.

c) The width of the confidence interval becomes narrower when the sample size n increases.

The above statement is true as the sample size increases the standard error decreases and the confidence interval become narrower.

8 0

3 years ago

A Monopoly player claims that the probability of getting a 2 when rolling a six-sided die is one sixth because the die is equal

Kisachek [45]

Answer:

<h2>It is Theoretical probability.</h2>

Step-by-step explanation:

Theoretical probability determines the likelihood of some incidents to happen.

Theoretical probability is the ratio between the total number of possible outcomes and the desired outcome.

Here, the desired outcome is getting a 2 that is only one desired outcome, where as total possible outcomes are 6. Here, the probability of getting a 2 is $\frac{1}{6}$ .

Empirical probability depends on observance. In the given question, nothing related to observance of the given incident has mentioned, hence it is not empirical probability.

8 0

3 years ago

#3-4 PLEASE HELP ASAP

Pie

Answer:

IDK

Step-by-step explanation:

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4 0

3 years ago

Find x: 3/(x-4)(x-7) + 6/(x-7)(x-13) + 15/(x-13)(x-28) - 1/x-28 = -1/20

Novay_Z [31]

The value of x<em> </em>in the polynomial fraction 3/((x-4)•(x-7)) + 6/((x-7)•(x-13)) + 15/((x-13)•(x-28)) - 1/(x-28) = -1/20 is <em>x </em>= 24

<h3>How can the polynomial with fractions be simplified to find<em> </em><em>x</em>?</h3>

The given equation is presented as follows;

$\frac{3}{(x - 4) \cdot (x - 7) } + \frac{6}{(x - 7) \cdot (x - 13) } + +\frac{15}{(x - 13) \cdot (x - 28) } - \frac{1}{(x - 28) } = - \frac{1}{20}$

Factoring the common denominator, we have;

$\frac{3\cdot(x - 13) \cdot(x - 28) + 6 \cdot(x - 4) \cdot(x - 28) + 15 \cdot(x - 4) \cdot(x - 7) - (x - 4) \cdot (x - 7)\cdot(x - 13)}{(x - 4) \cdot (x - 7)\cdot(x - 13) \cdot(x - 28)} + = - \frac{1}{20}$