Answer:
Therefore the function that models the height of the object after t seconds is given by "H(t) = 15 + 8.5*t + 16.09*t²".
Step-by-step explanation:
Since the object has a initial velocity and it's being accelerated by gravity, than it's height is defined by:
H(t) = H(0) + V(0)*t + 0.5*g*t²
Applying the data from the problem, we have:
H(t) = 15 + 8.5*t + 0.5*32.17405*t²
H(t) = 15 + 8.5*t + 16.09*t²
Therefore the function that models the height of the object after t seconds is given by "H(t) = 15 + 8.5*t + 16.09*t²".
Answer:
a. see attached
b. H(t) = 12 -10cos(πt/10)
c. H(16) ≈ 8.91 m
Step-by-step explanation:
<h3>a.</h3>
The cosine function has its extreme (positive) value when its argument is 0, so we like to use that function for circular motion problems that have an extreme value at t=0. The midline of the function needs to be adjusted upward from 0 to a value that is 2 m more than the 10 m radius. The amplitude of the function will be the 10 m radius. The period of the function is 20 seconds, so the cosine function will be scaled so that one full period is completed at t=20. That is, the argument of the cosine will be 2π(t/20) = πt/10.
The function describing the height will be ...
H(t) = 12 -10cos(πt/10)
The graph of it is attached.
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<h3>b. </h3>
See part a.
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<h3>c.</h3>
The wheel will reach the top of its travel after 1/2 of its period, or t=10. Then 6 seconds later is t=16.
H(16) = 12 -10cos(π(16/10) = 12 -10cos(1.6π) ≈ 12 -10(0.309017) ≈ 8.90983
The height of the rider 6 seconds after passing the top will be about 8.91 m.
Sheila is c+2 if that’s what your asking
He should use the Pythagorean Theorem to find the missing length.
Since KT is tangent to the circle and TL reaches the center of circle L, the measure of angle LTK is 90 degrees. This means that triangle LTK is a right triangle which means the Pythagorean Theorem can be used.
So,
TL²+(12)²=(13)²
=> TL²+144=169
=> TL²=25
=> TL = 5
Therefore, the radius of circle L is 5 feet.