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Delicious77 [7]
2 years ago
13

16.12 divided by 52 QUICK

Mathematics
2 answers:
Semenov [28]2 years ago
6 0
The answer to this is 0.31
Kitty [74]2 years ago
4 0

0.31

Ok Hope it’s correct ;)

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a standard six sided die. Janice rolled either a 2 or a 5 on the last 6 rolls of the die. What is the probability of Janice roll
Igoryamba

We have that   the probability of Janice rolling a 2 or 5 on her 7th toss of the dice is

\frac{1}{3}^7.

From the question we are told that

Janice rolled either a 2 or a 5 on the last 6 rolls of the die

Janice rolling a 2 or 5 on her 7th toss of the dice

P(2/ 5)=1/6+1/6\\\\P(2/ 5)=2/6\\\\P(2/ 5)=1/3.

Where

P(2/5 ) =(1/3)^6.

Janice roll the standard die 7th time the probability of getting 2 or 5 is

P(2/5 ) =\frac{1}{3}^7.

For more information on this visit

brainly.com/question/11234923?referrer=searchResults

7 0
2 years ago
Gravel is being dumped from a conveyor belt at a rate of 30 ft3/min, and its coarseness is such that it forms a pile in the shap
pogonyaev

Answer:

Rate of increase in height =\frac{dh}{dt}=0.3156ft/min

Step-by-step explanation:

we know that volume of a cone is given by

V=\frac{1}{12}\pi d^{2}h

It is Given that diameter equals height thus we have

V=\frac{1}{12}\pi h^{2}h\\\\V=\frac{1}{12}\pi h^{3}

Differentiating both sides with respect to time we get

\frac{dV}{dt}=\frac{1}{12}\pi \frac{dh^{3}}{dt}\\\\\frac{dV}{dt}=\frac{1}{12}\pi(3h^{2}\frac{dh}{dt})

Applying values and solving for \frac{dh}{dt} we get

\frac{dh}{dt}=\frac{12\frac{dV}{dt}}{3\pi h^{2}}\\\\\frac{dh}{dt}=0.3156ft/min

8 0
3 years ago
What table represents the relationship “A video game designer makes $35 per hour”?
photoshop1234 [79]

Answer:

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
These 2 questions are worth 35 points for the brainliest user. If you answer these two questions, I will answer any of yours for
elixir [45]

Answer:

1. 6,8,10

Step-by-step explanation:

1. 6,8,10

2. Scalene Triangle

4 0
3 years ago
Read 2 more answers
n=400 people under the age of 25 was asked whether they check social media sites right after they wake up. 42% check social medi
Aliun [14]

Answer:

Step-by-step explanation:

We would set up the hypothesis test.

For the null hypothesis,

p = 0.5

For the alternative hypothesis,

p < 0.5

Considering the population proportion, probability of success, p = 0.5

q = probability of failure = 1 - p

q = 1 - 0.5 = 0.5

Considering the sample,

P = 42/100 = 0.42

We would determine the test statistic which is the z score

z = (P - p)/√pq/n

n = 400

z = (0.42 - 0.5)/√(0.5 × 0.5)/400 = - 3.2

Recall, population proportion, p = 0.5

We want the area to the left of 0.5 since the alternative hypothesis is lesser than 0.5. Therefore, from the normal distribution table, the probability of getting a proportion < 0.5 is 0.00069

So p value = 0.00069

Since alpha, 0.05 > than the p value, 0.00069, then we would reject the null hypothesis.

Therefore, there is significant evidence to conclude that that less than 50% of people under the age of 25 check social media sites right after they wake up.

7 0
3 years ago
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