The answer to your question is option d as x is positive ( making it open up), and the vertex is (-3,-4)
Answer:
Ok so it would be square root 1
Step-by-step explanation:
Given that the sides of the acute triangle are as follows:
21 cm
x cm
2x cm
Stated that 21 cm is one of the shorter sides of the triangle2x is greater than x, so it follows that 2x MUST be the longest side
For acute triangles, the longest side must be less than the sum of the 2 shorter sides
Therefore, 2x < x + 21cm
2x – x < 21cm
x < 21cm
If x < 21cm, then 2x < 42cm
Therefore, the longest possible length for the longest side is 42cm
Answer:
32.4
Step-by-step explanation:
14 3/5 = 14.6
14.6*6=87.6
120-87.6=32.4
Answer:
i = 75.7°
h = 48.2°
Step-by-step explanation:
==>To find i, use the sine rule for finding angles: sin(A)/a = sin(B)/b
Where,
a = 7.2cm
sin(A) = i
b = 6.5cm
sin(B) = sin(61) = 0.8746
Thus:
sin(A)/7.2 = 0.8746/6.5
Multiply both sides by 7.2
sin(A) = (0.8746*7.2)/6.5
sin(A) = 0.969 (3 s.f)
A = i° = sin^-1(0.969) = 75.7 (3 s.f)
==>To find h, use the Cosine rule for angles:
Cos(C) = (a²+b²-c²)/2ab
cos(C) = h°, a = 4, b = 4.5, c = 3.5
a² = 16
b² = 20.25
c² = 12.25
cos(C) = (16+20.25-12.25)/(2*4*4.5)
cos(C) = 24/36
cos(C) = 0.667 (3 s.f)
C = h° = cos^-1(0.667) = 48.2° (3 s.f)
