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Elenna [48]
3 years ago
13

If P(x) = x² + x + 1 and Q(x) = 4x² - 1, find P(6).

Mathematics
2 answers:
alexandr402 [8]3 years ago
6 0
43 as you substitute 6 in place of x, and then get 36+6+1=43
Cerrena [4.2K]3 years ago
5 0

Answer:

P(6)=6^{2}+6+1=36+6+1=43

Q(6)=4*6^{2}-1=4*36-1=144-1=143

Step-by-step explanation: you must set the value of x=6

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Solve for X......:) <3
Vedmedyk [2.9K]

Answer:

x = 88

Step-by-step explanation:

All angles in a triangle equal 180 degrees. So our equation will be:

x + 48 + (x - 44) = 180

x + 48 + x - 44 = 180

2x + 48 - 44 = 180

2x + 4 = 180

2x = 176

x = 88

Hope this helps!

8 0
3 years ago
On a field trip, there were five girls for every eight boys. How many girls attended the 130 student field trip
yarga [219]
26 because 5 gose in to 13 2 times and you have 3 left bring down the zero for 30 and 6 gose in to it evenly
6 0
3 years ago
I need help for 2,3,4 and 5
hoa [83]

Answer:

2 is 12 3 is 3 faces 4 is 151  that's all   i can tell u at least i helped

Step-by-step explanation:

5 0
3 years ago
If g(x)=x+1/x-2 and h(x) = 4 – x, what is the value of (gxh) (-3)
suter [353]

For this case we have the following functions:

g (x) = \frac {x + 1} {x-2}\\h (x) = 4-x

We must find (g * h) (x)

By definition we have to:

(g * h) (x) = g (x) * h (x)

So:

(g * h) (x) = \frac {(x + 1) (4-x)} {x-2}

Now, we evaluate the function at x = -3:

(g * h) (- 3) = \frac {(- 3 + 1) (4 - (- 3))} {- 3-2}\\(g * h) (- 3) = \frac {(- 2) (4 + 3)} {- 5}\\(g * h) (- 3) = \frac {(- 2) (7)} {- 5}\\(g * h) (- 3) = \frac {-14} {- 5}\\(g * h) (- 3) = \frac {14} {5}

Answer:

(g * h) (- 3) = \frac {14} {5}

3 0
3 years ago
The element plutonium-239 is highly radioactive. Nuclear reactors
Dominik [7]

Answer:

2.84\cdot 10^{-5} y^{-1}

Step-by-step explanation:

The decay rate of a radioactive isotope (also called activity of the isotope) is given by:

r=k N

where

r is the decay rate

k is the decay constant

N is the number of nuclei in the radioactive sample

The decay constant of a radioactive isotope is also related to the half-life of the isotope by the formula

k=\frac{ln2}{t_{1/2}}

where

t_{1/2} is the half-life of the isotope, which is the time taken for the sample to halve, compared to its initial amount

In this problem, the half-life of plutioniun-239 is

t_{1/2}=24,360 y

Therefore, the k-factor (decay constant) is:

k=\frac{ln 2}{24,360}=2.84\cdot 10^{-5} y^{-1}

7 0
3 years ago
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