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Anvisha [2.4K]
3 years ago
14

Masón has planted 6 rows in the vegetable garden. He continues to work, planting 1 row every 2 hours. Write an equation to repre

sent this situation
Mathematics
1 answer:
Sophie [7]3 years ago
5 0
Y=.5x+6

I believe this is right sorry if it’s not.
You might be interested in
Geometry
trapecia [35]

Answer:

EF = 8

Step-by-step explanation:

The following data were obtained from the question:

EF = 2x

FG = 8

EG = 4x

EF =?

To obtain the value of EF, we shall first, obtain the value of x. This can be obtained as follow:

EG = EF + FG

EF = 2x

FG = 8

EG = 4x

4x = 2x + 8

Collect like terms

4x – 2x = 8

2x = 8

Divide both side by 2

x = 8/2

x = 4

Therefore, the value of x is 4.

Finally, we shall determine the the value of EF as follow:

EF = 2x

x = 4

EF = 2x

EF = 2(4)

EF = 8

**** Check ****

EG = EF + FG

EF = 2x

EG = 4x

FG = 8

4x = 2x + 8

x = 4

4(4) = 2(4) + 8

16 = 8 + 8

16 = 16

4 0
3 years ago
What is ? |-15| + |-1| =
balu736 [363]

Answer:16

Step-by-step explanation:The lines that are outside of the numbers keep the numbers positive so if you change them to positive number (15+1) you can add them and it gives you 16

8 0
3 years ago
Read 2 more answers
Please help will give brainliest<br> And happy Halloween
kramer
Answer to the problem is s=0.6
3 0
3 years ago
Read 2 more answers
One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on
irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna  =  237.08 ft

Step-by-step explanation:

​The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°  

distance from her position to the top of the building  = 2475 ft

distance from her position to the top of the flag  = 2615 ft

​(a) How far away from the base of the building is the surveyor​ located?​

using the SOHCAHTOA principle

cos 34° = c/2475

c =  0.8290375726  × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the​ building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b =  0.5591929035  × 2475

b =  1384.0024361

b =  1384.00 ft

​(c) What is the angle of elevation from the surveyor to the top of the​ antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ =  0.784665392

∅ = cos-1  0.784665392

∅ =   38.310258303

∅ =  38.31°

​(d) How tall is the​ antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) =  0.6199159917  × 2615

(a + b) =  1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00  =  237.08031822 ft

Height of antenna  =  237.08 ft

8 0
3 years ago
The angle of depression from the top of a cliff to an ant on the ground is 35 degrees. If the ant is 280 ft from the base of the
Burka [1]

Answer: 315

Step-by-step explanation: hope this is right.

5 0
3 years ago
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