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4 years ago

I could use some help with this question.

Mathematics

2 answers:

LUCKY_DIMON [66]4 years ago

8 0

750 * 4. :D Hope this helped.

likoan [24]4 years ago

7 0

It sounds like you just multiply by 2, so it would be 1500.

You might be interested in

Consider generating length-7 strings of lowercase letters. How many strings are there that either begin with 2 consonants or end

Semmy [17]

Answer:

5259544316

Step-by-step explanation:

Given that:

Length of string = 7

Either begins with 2 consonants or ends with 2 vowels :

Either or :

A U B = A + B - (AnB)

Number of vowels in alphabet = 5

Number of consonants = 21

2 consonants at beginning :

First 2 consonants, then the rest could be any:

21 * 21 * 26 * 26 * 26 * 26 * 26 = 5239686816

3 vowels at the end :

First 4 letters could be any alphabet ; last 3 should be vowels.:

26 * 26 * 26 * 26 * 5 * 5 * 5 = 57122000

2 consonants at beginning and 3 vowels at the end :

21 * 21 * 26 *26 *5* 5 * 5 = 37264500

Hence,

2 consonants at beginning + 3 vowels at end 2 consonants at beginning - 2 consonants at beginning and 3 vowels At end

(5239686816 + 57122000) - 37264500

= 5259544316

Hence, number of 7 alphabet strings that begins with 2 consonants and end with 3 vowels = 5259544316

7 0

3 years ago

Can someone help me please?

stich3 [128]

Have you tried asking a teacher for help before this

and did you try to take notes cuse notes are your best friends

6 0

3 years ago

Read 2 more answers

Round 694,553 to the nearest hundred thousand.

docker41 [41]

Answer:

pretty sure its 700,000

4 0

3 years ago

The table below shows the number of tickets sold per

andrew11 [14]

Answer:

102 tickets

Step-by-step explanation:

start by adding

Mon 198

Tues 96

We'd 204

then you would get 498 and max people that can fit in the gym is 600 so then you would subtract 600-498 and get 102 so the maximum amount of tickets they can sell on Thursday is 102 tickets

4 0

3 years ago

Can you answer this question as soon as possible.

Whitepunk [10]

Answer:

The intensity of the first earthquake is 6.31 times the second one

Step-by-step explanation:

The given formulae is M=log( $\frac{I}{S}$ )

Here for both the earthquakes the value of S is same.

Let the Intensity of the first earthquake be I1 and the second be I2.

Given M1=7.5

M2=6.7

Now M1=log( $\frac{I1}{S}$ )------1

M2=log( $\frac{I2}{S}$ )-----2

Now subtract 1 and 2 we get

M1-M2=log( $\frac{I1}{I2}$ )

I1/I2= $10^{M1-M2}$

I1=I2( $10^{0.8}$

I1=I2*6.31

6 0

3 years ago