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3 years ago

What is the measure of jk

Mathematics

1 answer:

Rashid [163]3 years ago

8 0

Well we know that the circle is equal to 360 and it is cut in half by JM but we also know that NM is the same as MK and half of 360 is 180 and 180 -55 =125 so jk equals 125

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ANSWER PLEASEEEE which test can be done to both sides of the equation to determine the value of x 3.2 x minus 9.6 equals 38.4

lorasvet [3.4K]

Answer: Answer A.

Step-by-step explanation:

3.2x-9.6=38.4

3.2x=48

x=15

8 0

3 years ago

A building has n floors numbered 1,2,...,n, plus a ground floor g. at the ground floor, m people get on the elevator together, a

fomenos

Let $X_i$ be the random variable indicating whether the elevator does not stop at floor $i$ , with

$X_i=\begin{cases}1&\text{if the elevator does not stop at floor }i\\0&\text{otherwise}\end{cases}$

Let $Y$ be the random variable representing the number of floors at which the elevator does not stop. Then

$Y=X_1+X_2+\cdots+X_{n-1}+X_n$

We want to find $\mathrm{Var}(Y)$ . By definition,

$\mathrm{Var}(Y)=\mathbb E[(Y-\mathbb E[Y])^2]=\mathbb E[Y^2]-\mathbb E[Y]^2$

As stated in the question, there is a $\dfrac1n$ probability that any one person will get off at floor $n$ (here, $n$ refers to any of the $n$ total floors, not just the top floor). Then the probability that a person will not get off at floor $n$ is $1-\dfrac1n$ . There are $m$ people in the elevator, so the probability that not a single one gets off at floor $n$ is $\left(1-\dfrac1n\right)^m$ .

So,

$\mathbb P(X_i=x)\begin{cases}\left(1-\dfrac1n\right)^m&\text{for }x=1\\\\1-\left(1-\dfrac1n\right)^m&\text{for }x=0\end{cases}$

which means

$\mathbb E[Y]=\mathbb E\left[\displaystyle\sum_{i=1}^nX_i\right]=\displaystyle\sum_{i=1}^n\mathbb E[X_i]=\sum_{i=1}^n\left(1\cdot\left(1-\dfrac1n\right)^m+0\cdot\left(1-\left(1-\dfrac1n\right)^m\right)$
$\implies\mathbb E[Y]=n\left(1-\dfrac1n\right)^m$

and

$\mathbb E[Y^2]=\mathbb E\left[\left(\displaystyle\sum_{i=1}^n{X_i}\right)^2\right]=\mathbb E\left[\displaystyle\sum_{i=1}^n{X_i}^2+2\sum_{1\le i$

Computing $\mathbb E[{X_i}^2]$ is trivial since it's the same as $\mathbb E[X_i]$ . (Do you see why?)

Next, we want to find the expected value of the following random variable, when $i\neq j$ :

$X_iX_j=\begin{cases}1&\text{if }X_i=1\text{ and }X_j=1\\0&\text{otherwise}\end{cases}$

If $X_iX_j=0$ , we don't care; when we compute $\mathbb E[X_iX_j]$ , the contributing terms will vanish. We only want to see what happens when both floors are not visited.

$\mathbb P(X_iX_j=1)=\left(1-\dfrac2n\right)^m$
$\implies\mathbb E[X_iX_j]=\left(1-\dfrac2n\right)^m$
$\implies2\displaystyle\sum_{1\le i$

where we multiply by $n(n-1)$ because that's how many ways there are of choosing indices $i,j$ for $X_iX_j$ such that $1\le i$ .

So,

$\mathrm{Var}[Y]=n\left(1-\dfrac1n\right)^m+2n(n-1)\left(1-\dfrac2n\right)^m-n^2\left(1-\dfrac1n\right)^{2m}$

4 0

3 years ago

Let A = {June, Janet, Jill, Justin, Jeffrey, Jelly}, B = {Janet, Jelly, Justin}, and C = {Irina, Irena, Arena, Arina, Jelly}. Fi

Hoochie [10]

Answer:

{June, Janet, Jill, Justin, Jeffrey, Jelly,Irina, Irena, Arena, Arina, }

Step-by-step explanation:

A ∪ C

This means union so we join the sets together

A = {June, Janet, Jill, Justin, Jeffrey, Jelly} + C = {Irina, Irena, Arena, Arina, Jelly}

A U C = {June, Janet, Jill, Justin, Jeffrey, Jelly,Irina, Irena, Arena, Arina, Jelly}

We get rid of repeats

A U C = {June, Janet, Jill, Justin, Jeffrey, Jelly,Irina, Irena, Arena, Arina, }

5 0

4 years ago

Addison is making Caramel apples. She has 2 1/2 bags of apples. One bag has 8 apples, and each apple weighs 5 ounces

andrey2020 [161]

Answer:

The expression that can be used is :

Number of bags x Number of apples in a bag x Weight of 1 apple

The total weight of apples in 2 1/2 bags of apples = 100 ounces.

Step-by-step explanation:

The given question is INCOMPLETE.

Addison is making caramel apples. She has 2 1/2 bags of apples. One full bag has 8 apples, and each apple weighs 5 ounces. Write an expression that could be used to find the total number of ounces of apples Addison has. Then find the total number of ounces.

Now, here the weight of 1 apple = 5 ounces

1 bag = 8 apples

⇒ Weight of 8 apples = 8 x ( weight of 1 apple) = 8 x (5 oz) = 40 oz

⇒ Total weight of 1 bag of apples = 40 oz

Now, the total bags of Apples Addison has = 2 1/2 bag

= 2 + 1/2 bag = 2. 5 bag

So, the weight of apples in 2.5 such bags = 2.5 x ( Weight in 1 bag)

= 2.5 ( 40 oz) = 100 oz

Hence, the total weight of apples in 2 1/2 bag = 100 ounces.

The expression that can be used

= Number of bags x Number of apples in a bag x Weight of 1 apple

= 2 1/2 x 8 x (5 oz)

3 0

4 years ago

6) y = -5(x + 7)<br> Is it linear

Firdavs [7]

Answer:yes

Step-by-step explanation:

It has the y=mx+b format

5 0

3 years ago