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Nostrana [21]
3 years ago
15

Having one password for all accounts is an easy way to remember passwords, but it will expose you to what risk?

Computers and Technology
1 answer:
Gwar [14]3 years ago
3 0
<span>Having one password for all accounts is an easy way to remember passwords, but it will expose you to the risk of losing all of your accounts. If a person hacks one of your accounts, then they will have access to everything you own. </span>
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One interesting application of computers is to display graphs and bar charts. Write an application that reads five numbers betwe
Nezavi [6.7K]

Answer:

The answer to this question can be given by program that  are as follows

import java.util.*;

//import package for taking input from user.

public class Main   //define class

{

public static void main (String ag[] )   //define main function

{

 int number;

 Scanner input = new Scanner(System.in);

 for (int i = 0; i < 5; i ++)                       //loo for input.

 {

  System.out.print ("Enter a number between 1 - 30:  ");

  number = input.nextInt();          //input number by the user.

 

 }

 asterisk();           //calling function.

 }

public static void asterisk()          //defination of function.

{

    //body of function.

    int n;                   //local variable.

 for (n= 0; n <= 30; n++)                  //using loop for print asterisk

 {

 if (n !=0)

 //printf used for print value.

 System.out.printf("*", n );                  //print value.

 }

 

  for (n= 0; n <= 30; n++)         //using loop for print asterisk

  {

 if (n !=0)

 //printf used for print value.

 System.out.printf("*", n );     //print value.

 }

 

  for (n= 0; n <= 30; n++)          //using loop for print asterisk

  {

 if (n !=0)

 //printf used for print value.

 System.out.printf("*", n );          //print value.

 }

  for (n= 0; n <= 30; n++)            //using loop for print asterisk

 

 {

 if (n !=0)

 //printf used for print value.

 System.out.printf("*", n );               //print value.

 }

 

  for (n= 0; n <= 30; n++)             //using loop for print asterisk

  {

 if (n !=0)

 //printf used for print value.

 System.out.printf("*", n );             //print value.

 }

}

}

Output:

Enter a number between 1 - 30: 2

Enter a number between 1 - 30: 2

Enter a number between 1 - 30: 1  

Enter a number between 1 - 30: 3

Enter a number between 1 - 30: 4

*******************************************************************************

Explanation:

In this program we take 5 time input from the user and print the value in the form of (*) that can be explain in above output section.In that program we use printf method that is also used for print the value.

3 0
3 years ago
A shuffle of two strings X and Y is formed by interspersing the characters into a new string, keeping the characters of X and Y
levacccp [35]

Shuffle (A[1..m], B[1..n], C[1..m+n]):

Shuf[0, 0] ← True

for j ← 1 to n

Shuf[0, j] ← Shuf[0, j − 1] ∧ (B[j] = C[j])

for i ← 1 to n

Shuf[i, 0] ← Shuf[i − 1, 0] ∧ (A[i] = B[i])

for j ← 1 to n

Shuf[i, j] ← False

if A[i] = C[i + j]

Shuf[i, j] ← Shuf[i, j] ∨ Shuf[i − 1, j]

if B[i] = C[i + j]

Shuf[i, j] ← Shuf[i, j] ∨ Shuf[i, j − 1]

return Shuf[m, n]

The algorithm runs in O(mn) time.

3 0
3 years ago
What is the correct syntax to take the first five characters from the cell A2 and place it to its right in cell A3? =RIGHT(A3,5)
vfiekz [6]

Answer:=LEFT(A2,5)

Explanation:

8 0
3 years ago
Read 2 more answers
This program needs to be written in Java. Along with NO For/while loops, and no methods.
Umnica [9.8K]
The only way without a while loop and no method I can think of is use switch with every possible variation of the four digit binary which is 15.

Here is the starter code:

import java.util.Scanner;
public class MyClass {
public static void main(String args[]) {
Scanner sc = new Scanner(System.in);
int digit = sc.nextInt();
switch(digit) {
case 0000:
System.out.println("0");
break;
case 0001:
System.out.println("1");
break;
case 0010:
System.out.println("2");
break;
case 0011:
System.out.println("3");
break;
case 0100:
System.out.println("4");
break;

… (fill in other cases)


}
}
}

Use this link: https://www.electronics-tutorials.ws/binary/bin_3.html

There might be a better way, but without loops or methods this is all I got.
6 0
2 years ago
50 POINTS!!!!! WILL MARK BRAINLIEST!!!!!HURRY!!!!!
Mazyrski [523]

Answer:

It’s control

Explanation:

E2020 told me

7 0
3 years ago
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