<span>, y+2 = (x^2/2) - 2sin(y)
so we are taking the derivative y in respect to x so we have
dy/dx use chain rule on y
so y' = 2x/2 - 2cos(y)*y'
</span><span>Now rearrange it to solve for y'
y' = 2x/2 - 2cos(y)*y'
0 = x - 2cos(y)y' - y'
- x = 2cos(y)y' - y'
-x = y'(2cos(y) - 1)
-x/(2cos(y) - 1) = y'
</span><span>we know when f(2) = 0 so thus y = 0
so when
f'(2) = -2/(2cos(0)-1)
</span><span>2/2 = 1
</span><span>f'(2) = -2/(2cos(0)-1)
cos(0) = 1
thus
f'(2) = -2/(2(1)-1)
= -2/-1
= 2
f'(2) = 2
</span>
Distribute 1/4 by multiplying it by 8, -6X and 20 you end up with
1/4times8=2
1/4times-6x= -1.5x
1/4times20=5
so 2-1.5x+5
add 2 and 5 to get 7
the answer is -1.5x+7
A+b=-10
ab=-75
a=-75/b
-75/b + b = -10
-75/b + b²/b = -10b/b
b²+10b-75=0
(b+15)(b-5)=0
b+15=0 or b-5=0,
b= -15, a=5
The first one is 22 the second one is 16 the third one is 18
