3 years ago

Is 21/5 a rational number

Mathematics

1 answer:

Anastaziya [24]3 years ago

8 0

The number 21/5 is a rational number because it can be simplified down to 4.2, or 21/5

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1 year ago

simplify (x − 2)(x + 9) using the table method, and identify the resulting expression in standard form.

NeX [460]

Answer:

this should be right if not comment and I'll relook it.

FOIL Method.

You will get the same answer x^2+ 7x- 18

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3 years ago

Read 2 more answers

What is the following quotient?<br><br> Square root of 120/square root of 30

Mekhanik [1.2K]

Answer:

The square root of 120 is 10.9545.

The square root of 30 is 5.47723.

10.9545 divided by 5.47723 is approximately 2.0000073

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3 years ago

A=867.456 b=9846.5579<br><br>axb

MAXImum [283]

Answer is
$0.85414557297024 \times {10}^{7}$
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3 years ago

Find the limit, if it exists. (If an answer does not exist, enter DNE.)

gavmur [86]

Answer:

$\lim\limits_{(x,y)\rightarrow(0,0)}\left(\sqrt{x^2+y^2+49}+7\right)=14$

Step-by-step explanation:

to find the limit:

$\lim\limits_{(x,y)\rightarrow(0,0)}\left(\dfrac{x^2+y^2}{\sqrt{x^2+y^2+49}-7}\right)$

we need to first rationalize our expression.

$\dfrac{x^2+y^2}{\sqrt{x^2+y^2+49}-7}\left(\dfrac{\sqrt{x^2+y^2+49}+7}{\sqrt{x^2+y^2+49}+7}\right)$

$\dfrac{(x^2+y^2)(\sqrt{x^2+y^2+49}+7)}{(\sqrt{x^2+y^2+49}\,)^2-7^2}$

$\dfrac{(x^2+y^2)(\sqrt{x^2+y^2+49}+7)}{(x^2+y^2)}$

$\sqrt{x^2+y^2+49}+7$

Now this is our simplified expression, we can use our limit now.

$\lim\limits_{(x,y)\rightarrow(0,0)}\left(\sqrt{x^2+y^2+49}+7\right)\\\sqrt{0^2+0^2+49+7}\\7+7\\14$

Limit exists and it is 14 at (0,0)

4 0

3 years ago