Answer:
E(X) = 6
Var(X) = 3.394
Step-by-step explanation:
Let X represent the number of carp caught out of the 20 fishes caught. Now, if we are to assume that each
of the (100, 20) ways to catch the 20 fishes will be equally likely.
Thus, we can say that X fulfills a hypergeometric
distribution with parameters as follows;
n = 20, N = 100, k = 30
Formula for expected mean value in hypergeometric distribution is;
E(X) = nk/N
E(X) = (20 × 30)/100
E(X) = 6
Formula for variance is;
Var(X) = (nk/N) × [((n - 1)(k - 1)/(N-1))) + (1 - nk/N)]
Var(X) = ((20 × 30)/100) × [((20 - 1)(30 - 1)/(100 - 1)) + (1 - (20 × 30/100)]
Var(X) = 6 × 0.5657
Var(X) = 3.394
7.96 / 6 = 1.33 <== unit rate
Convert both perecentages to decimal form by dividing each of them by 100 to get 0.60 and 0.65. Next, multiply by 0.60 and 0.65 to get 0.39. Multiply the product by 100 to get the percentage form, 39%. So, the answer is 39%.
Answer:
Option B
Step-by-step explanation:
Slope
And
These are acceleration
Y intercept is (0,2) as x coordinate is 0
This is initial velocity 2m/s
The runner stopped at 8s
