F(x)= x² + 5, is just a parabola shfited upwards by 5 units, so, is a smooth graph and no abrupt edges, so from 0 to 3, is indeed differentiable and continuous. So Rolle's theorem applies, let's check for "c" by simply setting its variable to 0, bear in mind that, looking for "c" in this context, is really just looking for a critical point, since we're just looking where f'(c) = 0, and is a horizontal tangent line.
Isolate the x. Subtract 3x from both sides, and add 4 to both sides
-2x (-3x) - 4 (+4) < 3x (-3x) + 21 (+4)
-2x - 3x < 21 + 4
Simplify. Combine like terms
-5x < 25
Isolate the x. Divide -5 from both sides (remember to flip the sign).
-5x/-5 < 25/-5
x > 25/-5
x > -5
x > -5 is your answer
hope this helps
Multiply -1 by -7
-9x^3 + 8x^2 - 7x/6 + 7
Answer:
Reason SAS postulate
Step-by-step explanation:
The two triangles must be congruent.
Reason: SAS postulate
