<h2><u>
Solution</u>
:</h2>
<em>To find the zero,</em>
<em>x</em> + 1 - 4 = 0
<em>x</em> = 4 - 1
<em>x</em> = 3
3 is the <u>root</u> of <em>(x + 1) - 4</em>.
<span>There are three possibilities.
1. Of the 30 bikes that needed gear repairs, 20 also needed tires.
2. Of the 30 bikes that needed gear repairs, 10 also needed tires.
3. Of the 30 bikes that needed gear repairs, between 10 and 20 also needed tires.</span>
Answer:
D
Step-by-step explanation:
![f(x)=(x-1)(x^2+2)^3\\f'(x)=(x-1)*3(x^2+2)^2*2x+(x^2+2)^3*1\\f'(x)=6x(x-1)(x^2+2)^2+(x^2+2)^3\\f'(x)=(x^2+2)^2[6x^2-6x+x^2+2]\\f'(x)=(x^2+2)^2(7x^2-6x+2)\\D](https://tex.z-dn.net/?f=f%28x%29%3D%28x-1%29%28x%5E2%2B2%29%5E3%5C%5Cf%27%28x%29%3D%28x-1%29%2A3%28x%5E2%2B2%29%5E2%2A2x%2B%28x%5E2%2B2%29%5E3%2A1%5C%5Cf%27%28x%29%3D6x%28x-1%29%28x%5E2%2B2%29%5E2%2B%28x%5E2%2B2%29%5E3%5C%5Cf%27%28x%29%3D%28x%5E2%2B2%29%5E2%5B6x%5E2-6x%2Bx%5E2%2B2%5D%5C%5Cf%27%28x%29%3D%28x%5E2%2B2%29%5E2%287x%5E2-6x%2B2%29%5C%5CD)
The answer is sixteen thousand four hundred ninety
Answer is:
It includes points in quadrant II and it doesnt include points in quadrant I
Explanation:
For odd functions a rule is:
f(x) = -f(-x) or in other words
f(x) + f(-x) = 0
Because of this function can be in quadrants I and III or in quadrants II and IV as in pairs...
