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Alexandra [31]
3 years ago
15

Alguien me puede decir fracciones equivalentes a 2/7

Mathematics
2 answers:
Tresset [83]3 years ago
8 0
4/14, 6/21, 8/28, etc. Just multiply both numerator and denominator by the same number.
trasher [3.6K]3 years ago
8 0
4/14, 6/21, 8/28, 10/35 etc...
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3 pens cost $2.70. What is the cost per pen?
marissa [1.9K]
2, 70$ : 3 = 0, 9o $The total cost for each pen 
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3 0
3 years ago
Use the quadratic formula to find the solutions to the quadratic equation below x^2-6x-5=0
Sonja [21]

Answer:

\large\boxed{x=3-\sqrt{14}\ \vee\ x=3+\sqrt{14}}

Step-by-step explanation:

x^2-6x-5=0\qquad\text{add 5 to both sides}\\\\x^2-6x=5\\\\x^2-2(x)(3)=5\qquad\text{add}\ 3^2\ \text{to both sides}\\\\x^2-2(x)(3)+3^2=5+3^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\(x-3)^2=5+9\\\\(x-3)^2=14\to x-3=\pm\sqrt{14}\qquad\text{add 3 to both sides}\\\\x=3-\sqrt{14}\ \vee\ x=3+\sqrt{14}

8 0
3 years ago
Use the Pythagorean identity to do the following:
nlexa [21]

Answer:  2 - 2*sin³(θ) - √1 -sin²(θ)

Step-by-step explanation:  In the expression

cos(theta)*sin2(theta) − cos(theta)

sin (2θ) = 2 sin(θ)*cos(θ)     ⇒   cos(θ)*2sin(θ)cos(θ) - cos(θ)

2cos²(θ)sin(θ) - cos(θ)           if we use cos²(θ) = 1-sin²(θ)

2 [ (1 - sin²(θ))*sin(θ)] - cos(θ)

2  - 2sin²(θ)sin(θ) - cos(θ)  ⇒  2-2sin³(θ)-cos(θ)   ;  cos(θ) = √1 -sin²(θ)

2 - 2*sin³(θ) - √1 -sin²(θ)

7 0
3 years ago
Which graph shows the solution to the inequality Negative 3 x minus 7 less-than 20
mart [117]

Answer:

qw567

Step-by-step explanation:

8 0
3 years ago
Look at the diagram. If RS= 8y + 4, ST = 4y + 8, and RT = 36, find the value of y.
vladimir2022 [97]
<span>RS= 8y + 4, ST = 4y + 8, and RT = 36

RS + ST = RT
</span>8y + 4 + 4y + 8 = 36
12y + 12 = 36
12y = 24
    y = 2

answer
y = 2 (first choice)
6 0
3 years ago
Read 2 more answers
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