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Anettt [7]
3 years ago
12

Make b the subject of the formula P=2a+b

Mathematics
2 answers:
Gelneren [198K]3 years ago
5 0
In order to make b the subject of this equation, we must isolate it on the left side. We can do this by following these steps:

P = 2a+b

Subtract b from both sides

P - b = 2a+b-b

P-b=2a

Subtract P from both sides

P-b-P=2a-P

-b=2a-P

Now, we have isolated b, but it is negative. We can fix this by multiplying both sides of the equation by -1.

-(-b)=-(2a-P)

b=-2a+P

Which is your final answer.
b = -2a+P.
Hope that helped! =)
andrey2020 [161]3 years ago
4 0
If you're trying to isolate b, then you can do the following:

P=2a+b
P-2a=b
b=P-2a

But I'm not sure if that's what it is asking you to do.
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To find the surface area of the pyramid, in square inches, Vikram wrote (33.2) (34.2) + 4 (one-half (34.2) (28.4)). What error d
madam [21]

Answer:

B. He used the wrong expression to represent the area of the base of the pyramid.

Step-by-step explanation:

Given

See attachment for pyramid

Area = (33.2)(34.2) + 4 * \frac{1}{2} * 34.4 * 28.4

Required

Vikram's error

The surface area of a square pyramid is:

Area = Base\ Area + 4 * Area \triangle

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Base\ Area = Length * Length

Base\ Area = 34.2 * 34.2

4 * Area \triangle = 4 * \frac{1}{2} * Base * Height

4 * Area \triangle = 4 * \frac{1}{2} * 34.2 * 28.4

So:

Area = Base\ Area + 4 * Area \triangle

Area = 34.2 * 34.2 + 4 * \frac{1}{2} * 34.2 * 28.4

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3 years ago
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<h3>2 Answers: Choice C and choice D</h3>

y = csc(x) and y = sec(x)

==========================================================

Explanation:

The term "zeroes" in this case is the same as "roots" and "x intercepts". Any root is of the form (k, 0), where k is some real number. A root always occurs when y = 0.

Use GeoGebra, Desmos, or any graphing tool you prefer. If you graphed y = cos(x), you'll see that the curve crosses the x axis infinitely many times. Therefore, it has infinitely many roots. We can cross choice A off the list.

The same applies to...

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So we can rule out choices B, E and F.

Only choice C and D have graphs that do not have any x intercepts at all.

------------

If you're curious why csc doesn't have any roots, consider the fact that

csc(x) = 1/sin(x)

and ask yourself "when is that fraction equal to zero?". The answer is "never" because the numerator is always 1, and the denominator cannot be zero. If the denominator were zero, then we'd have a division by zero error. So that's why csc(x) can't ever be zero. The same applies to sec(x) as well.

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