Make b the subject of the formula P=2a+b

2 answers:

5 0

In order to make b the subject of this equation, we must isolate it on the left side. We can do this by following these steps:

$P = 2a+b$

Subtract b from both sides

$P - b = 2a+b-b$

$P-b=2a$

Subtract P from both sides

$P-b-P=2a-P$

$-b=2a-P$

Now, we have isolated b, but it is negative. We can fix this by multiplying both sides of the equation by -1.

$-(-b)=-(2a-P)$

$b=-2a+P$

Which is your final answer.
$b = -2a+P$ .
Hope that helped! =)

andrey2020 [161]2 years ago

4 0

If you're trying to isolate b, then you can do the following:

P=2a+b
P-2a=b
b=P-2a

But I'm not sure if that's what it is asking you to do.

You might be interested in

Write an equation that gives the overall equilibrium constant in terms of the equilibrium constants and . If you need to include

shutvik [7]

Answer:

The answer is " $k=k_1k_{2}^2$ "

Step-by-step explanation:

For point 1:

$4NHH_3 \ (g) +5O_2\ (g) \leftrightharpoons 4NO\ (g) +6H_2O \ (g)..................k_1\\\\$

For point 2:

$2 \times(2\ NO\ (o)+O_2 \ (g) \leftrightharpoons 2NO_2\ (g)) ..................K_2\\\\$

Adding $k_1$ equation and multiply by 2 in the equation $k_2$ so we get $\to 4NH_3\ (g) +7 O_2\ (g) \leftrightharpoons 4 NO_2\(g) +6H_2O\ (g)....... k\\\\k= k_1\times k_{2}^2\\\\k=k_1k_{2}^2\\\\$