Answer:
no, yes, yes, no
Step-by-step explanation:
BC is 3 units long, CA is 5 units long, BC is shorter than BA by a little over 3 units (use pythagorean theorem), and AC is longer than BC by 3 units not 2.
Answer:
7 ft 1 1/4 in
Step-by-step explanation:
The total width of 3 paintings and 2 spaces is ...
(10.5 in) + (3 in) + (3 ft 6 in) + (3 in) + (2 ft 2 3/4 in)
= (10.5 +3 +6 +3 +2.75) in + (3 +2) ft
= 25.25 in + 5 ft = 1.25 in + 24 in + 5 ft
= 7 ft 1 1/4 in
The total width of wall space needed for the paintings is 7 feet 1 1/4 inches.
_____
If two more 3-inch spaces are added, one on each end, then the total width is 7 feet 7 1/4 inches. The problem isn't clear about that, saying only that there are spaces between the paintings.
Y - y₁ = m(x - x₁)
y - 1 = -2(x - 3)
y - 1 = -2(x) + 2(3)
y - 1 = -2x + 6
+ 1 + 1
y = -2x + 7
The answer is A.
We are interested in selecting 2 people from the 7-person task force.
n = 7
r = 2
nPr = n! / (n-r)!
7!
------
(7-2)!
=
7!
----
5!
7×6×5×4×3×2×1
------------------------
5×4×3×2×1
= 7×6
= 42
Start by distributing the 6 through the parenthses on the left side.
So we have 6x + 24 = 30.
Solving from here, I would subtract 24 from both sides to get 6x = 6.
Finally, dividing both sides of the equation by 6, we have x = 1.
