Answer: 19 ≥ 3z + 1 ≥ - 5
Answer:
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Answer:
1) 250°, 2) 44°
Step-by-step explanation:
1) See attached
If we add a line ⊥ to both AB and DE, we can find x as a sum of 2 internal angles of right triangles and 180°
∠D internal = 360°-312°=48°
x=180°+(90°-62°)+(90°-48°)= 180°+28°+42°= 250°
x=250°
2)
∠ADC= ∠ABC= 180°- ∠ADE= 180°- 110°= 70°
∠DBC= ∠ABC- ∠ABD= 70°-26°= 44°
∠DBC= 44°
Now cos⁻¹(0.7) is about 45.6°, that's on the first quadrant.
keep in mind that the inverse cosine function has a range of [0, 180°], so any angles it will spit out, will be on either the I quadrant where cosine is positive or the II quadrant, where cosine is negative.
however, 45.6° has a twin, she's at the IV quadrant, where cosine is also positive, and that'd be 360° - 45.6°, or 314.4°.
now, those are the first two, but we have been only working on the [0, 360°] range.... but we can simply go around the circle many times over up to 720° or 72000000000° if we so wish, so let's go just one more time around the circle to find the other fellows.
360° + 45.6° is a full circle and 45.6° more, that will give us the other angle, also in the first quadrant, but after a full cycle, at 405.6°.
then to find her twin on the IV quadrant, we simply keep on going, and that'd be at 360° + 360° - 45.6°, 674.4°.
and you can keep on going around the circle, but only four are needed this time only.
