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Dovator [93]
3 years ago
11

He base of a pentagonal prism has an area of 2.4 m2. The prism has a volume of 4.8 m3. What is its height? Use sketches, formula

s and/or charts to justify your answer
Mathematics
1 answer:
77julia77 [94]3 years ago
3 0

Answer:

The height of the prism is 2m

Step-by-step explanation:

Given;

The volume of pentagonal prism, V = 4.8 m^3

Area of the prism, A = 2.4 m^2

To determine the height of the prism, we consider the following;

Volume of any prism = Area of the prism x height of the prism

Height of the prism = volume of the prism / Area of the prism

Height of the prism = 4.8 / 2.4

Height of the prism = 2 m

Therefore, the height of the prism is 2m

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3 0
2 years ago
PLZZZZZZ DONT SCROLLL HELP A SOUL OUT
nydimaria [60]

Answer:

15 units

Step-by-step explanation:

K(8, 6) and J(-4, -3)

Distance between 2 points

=  \sqrt{(x1 - x2)^{2}  +  {(y1 - y2)}^{2} }

Thus using the formula above,

distance between points J and K

=  \sqrt{ {[8- (-4)]}^{2}  +  {[6- (-3)]}^{2} }  \\  =  \sqrt{ {12}^{2}  +  {9}^{2} }  \\  =  \sqrt{225}  \\  = 15 \: units

8 0
3 years ago
Read 2 more answers
The market and Stock J have the following probability distributions:
denis-greek [22]

Answer:

1) E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

2) E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

3) E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

4) E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

Step-by-step explanation:

For this case we have the following distributions given:

Probability  M   J

0.3           14%  22%

0.4           10%    4%

0.3           19%    12%

Part 1

The expected value is given by this formula:

E(X)=\sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

Part 2

E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

Part 3

We can calculate the second moment first with the following formula:

E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

Part 4

We can calculate the second moment first with the following formula:

E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

8 0
3 years ago
Solve exponents please help just this one u get 10 points
STALIN [3.7K]
I think it's equal to 1 because every expression with the exponent of zero is equal to 1, idk for sure though
8 0
3 years ago
Finding dilations geometry​
cricket20 [7]

Answer:

3, 7

Step-by-step explanation:

6 0
3 years ago
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