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3 years ago

8

Find a positive number x such that the sum of 36x and 1 x is as small as possible.

1 answer:

Mekhanik [1.2K]3 years ago

6 0

The answer is zero, i think

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Do yall know this ?<br><br><br><br><br><br><br><br><br><br> (2)

Flauer [41]

Nope we don’t know that

6 0

2 years ago

how for is Blaine's house if you must drive 6.5 hours through the woods at an average of 45mph to get there?

omeli [17]

Six and a half hours at a speed of 45 mph. 45 mph is forty five miles per hour. since there are six full hours, multiply six (time) by speed (45) to get the distance within the six full hours, which is 270 miles. you also have an additional half hour at a 45 mph speed, so rather than going 45 miles in one hour, you for half an hour, meaning you go 22.5 miles. add these two together (270 + 22.5) to get 292.5 miles. a faster way to get to this would be to multiply 6.5 * 45. hole this helps!

3 0

3 years ago

HELP!!! PLZZ THIS IS SO FRICKIN HARD!

krek1111 [17]

Answer:

14.3%

Step-by-step explanation:

1/7=0.142857142857

round that to the nearest tenth and that is 0.143

make it a percentage and it is 14.3%

8 0

2 years ago

Simplify the expression state any excluded values<br> 2a^2-4a+2<br> ---------------<br> 3a^2-3

chubhunter [2.5K]

Answer:

The simplified form is $\dfrac{2(x-1)}{3(x+1)}$ .

$x =1$ is the excluded value for the given expression.

Step-by-step explanation:

Given:

The expression given is:

$\dfrac{2a^2-4a+2}{3a^2-3}$

Let us simplify the numerator and denominator separately.

The numerator is given as $2a^2-4a+2$

2 is a common factor in all the three terms. So, we factor it out. This gives,

$=2(a^2-2a+1)$

Now, $a^2-2a+1=(a-1)(a-1)$

Therefore, the numerator becomes $2(a-1)(a-1)$

The denominator is given as: $3a^2-3$

Factoring out 3, we get

$3(a^2-1)$

Now, $a^2-1$ is of the form $a^2-b^2=(a-b)(a+b)$

So, $a^2-1=(a-1)(a+1)$

Therefore, the denominator becomes $3(a-1)(a+1)$

Now, the given expression is simplified to:

$\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}$

There is $(x-1)$ in the numerator and denominator. We can cancel them only if $x\ne1$ as for $x=1$ , the given expression is undefined.

Now, cancelling the like terms considering $x\ne1$ , we get:

$\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}$

Therefore, the simplified form is $\dfrac{2(x-1)}{3(x+1)}$

The simplification is true only if $x\ne1$ . So, $x =1$ is the excluded value for the given expression.

8 0

3 years ago

5+656+-425*3/4<35-73*3/7

Komok [63]

The answer is false

if you solve both sides it says that 627.25 is less than 3.714 which isn't correct because 627.25 is obviously greater than 3.714

5 0

3 years ago