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Kitty [74]
3 years ago
7

How to solve 7^3x+4=49^2x+1

Mathematics
1 answer:
stiks02 [169]3 years ago
7 0
Raise 49<span> to the </span>power<span> of </span>2<span> to get </span><span>2401.
</span><span><span>7^3</span>x+4=2401x+1

</span>Raise 7<span> to the </span>power<span> of </span>3<span> to get </span><span>343.
</span><span>343x+4=2401x+1

</span>Since <span>2401x</span><span> contains the </span>variable<span> to solve for, move it to the left-hand side of the </span>equation<span> by subtracting </span><span>2401x</span><span> from both sides.
</span><span>343x+4−2401x=1

</span>Add <span>343x</span><span> and </span><span>−2401x</span><span> to get </span><span><span>−2058x</span>.
</span><span>−2058x+4=1

</span>Since 4<span> does not contain the </span>variable<span> to solve for, move it to the right-hand side of the </span>equation<span> by subtracting </span>4<span> from both sides.
</span><span>−2058x=−4+1

</span>Add <span>−4</span><span> and </span>1<span> to get </span><span><span>−3</span>.
</span><span>−2058x=−3

</span>Divide<span> each </span>term<span> in the </span>equation<span> by </span><span><span>−2058</span>.


</span><span>x=<span>1/686</span></span>
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