For this case we have an equation of the form:
h (t) = - (1/2) * a * t ^ 2 + vo * t + h0
Where,
vo: initial speed
a: acceleration:
h0: initial height.
We have the following equation:
h (t) = - 16t2 + 19t + 110
Therefore, the initial velocity is:
vo = 19 feet / s
Answer:
The initial velocity when the rock is thrown:
vo = 19 feet / s
It doesn't say anything about him.
Answer:
See below.
Step-by-step explanation:
Find two points on the graph that are easy to read.
Start at one point. You must now go to the other point, but you can only move vertically (up and down) and horizontally (right and left.)
Move vertically toward the other point. Count the number of units you moved. Up is positive, and down is negative. This is the rise.
Now move horizontally to the second point and count the units. Right is positive and left is negative. This is the run.
slope = rise/run
Answer is 0.89 sorry for bad drawing and putting 89 as the answer instead of 0.89
Answer:
y = - 
x + 2
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 3x - 3 ← is in slope- intercept form
with slope m = 3
Given a line with slope m then the slope of a line perpendicular to it is
= - 
= - , hence
y = - x + c ← is the partial equation of the perpendicular line
To find c substitute (3, 1) into the partial equation
1 = - 1 + c ⇒ c = 1 + 1 = 2
y = - x + 2 ← equation of perpendicular line
