Write a trinomial that has a factor of X +3 and a GCF of -5x

I have these factoring questions I need help with.

snow_lady [41]

$f(x)=4x^2+4x-3$

1. Determine y-intercept.

The y-intercept is (0,-3). Substitute x = 0 in the equation as we get f(x) = -3 as the y-intercept.

2. Determine the zeros.

Factor the polynomials first. $(2x-1)(2x+3)$ This is the factored form. The zeros are the roots of equation. Therefore, the zeros are 1/2 and -3/2

3. Determine the Axis of Symmetry

We can solve this by using the formula of $x=-\frac{b}{2a}$ However, I'll be solving the Axis of Symmetry with Calculus instead.

$f'(x)=2(4x^{2-1})+1(4x^{1-1})-0\\f'(x)=8x+4$

Then let f'(x) = 0 to find the Axis of Symmetry.

$8x+4=0\\8x=-4\\x=-\frac{4}{8}\\x=-\frac{1}{2}$

Therefore, the Axis of Symmetry is -1/2

4. Determine the vertex.

Substitute the value of Axis of Symmetry in f(x).

$f(x)=4(-\frac{1}{2})^2+4(-\frac{1}{2})-3\\f(x)=4(\frac{1}{4})-2-3\\f(x)=1-2-3\\f(x)=-4$

Therefore the vertex is at (-1/2, -4)

5. Does the vertex representing max-pont or min-point?

The vertex represents the minimum point. The graph is upward, meaning the minimum point is the point that gives the LOWEST Y-VALUE.

7. Graph f(x)

Unfortunately I won't be able to graph. But I can tell you to graph a parabola that has the most curve at the vertex and intercepts y-axis at (0,-3).

--------------------------- End of Part 1 --------------------------------

2. Write the general form of Quadratic Function in standard form.

$y=ax^2+bx+c$

The graph can be easily determined about the y-intercept and being an upward or downward parabola along with how narrow or wide the parabola is.

For example, c value is the y-intercept as defined. When a > 0, the parabola is upward and when a < 0, the parabola is downward. The more value of | a | is, the more narrow it will be and the less value of | a | it is, the wider it will be.

3. Write in Factored Form

$y=(x+a)(x+b)\\y=(x-a)(x-b)\\y=(x+a)(x-b)\\y=(x-a)(x+b)$

These are factored forms with different types of operators.

The equation can be easily determined about the roots of equation. For example, if the function is in f(x) = (x+2)(x-1) Then the roots would be x = -2 and 1 as the graph will intercept x-axis at (-2,0) and (1,0)

4. Write in Vertex Form.

$y=a(x-h)^2+k$

The equation can be easily determined for the vertex, axis of symmetry and the same narrow/wide/upward/downward parabola again.

The vertex is at (h,k) and the axis of symmetry is at x = h.

For example, $y=(x-2)^2+3$

The vertex would be at (2,3) and the axis of symmetry is x = 2.

3 0

3 years ago

Please help will mark Brainly

iris [78.8K]

The answer is D. For every week, she is giving away 10 pencils which means Mrs. Doyal is removing pencils from the 150 pencils she already has by “-10x”. Hope this helps c:

8 0

3 years ago

M/n x p for m = 10, n = -5, and p = -2

Novay_Z [31]

M / n x p = 10/-5 x -2 = -2 x -2 = 4

6 0

3 years ago

Will give alot of points!

Rom4ik [11]

I think you just multiply the amount of pennies for one grooming job by 9

3 0

3 years ago

Read 2 more answers

Conrad drew 2 angles. Three times the measure of angle 1 is 30° more than 5 times the measure of angle 2. The sum of twice the m

ad-work [718]

Let x= measure of angle 1
Let y= measure of angle 2

This is solving a system of equations

3x=30+ 5y which can also be written

3x-5y=30, and

2x+2y=180
There are a few ways to solve this, like solving for x in one of the equations and plugging it in for x in the other equation, but here is another way:
2(3x-5y)=2*30
3(2x+2y)= 3*180

6x-10y=60
6x+6y=540, and now subtract to get rid of x
0-16y=-480
Y=30
Plug it back in to either equation and you get x=60

3 0

3 years ago