Answer:
i think the answer is 392= 49/Q
Splitting up the interval of integration into 
subintervals gives the partition
![\left[0,\dfrac1n\right],\left[\dfrac1n,\dfrac2n\right],\ldots,\left[\dfrac{n-1}n,1\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%5Cdfrac1n%5Cright%5D%2C%5Cleft%5B%5Cdfrac1n%2C%5Cdfrac2n%5Cright%5D%2C%5Cldots%2C%5Cleft%5B%5Cdfrac%7Bn-1%7Dn%2C1%5Cright%5D)
Each subinterval has length 
. The right endpoints of each subinterval follow the sequence
with 
. Then the left-endpoint Riemann sum that approximates the definite integral is
and taking the limit as 
gives the area exactly. We have
Big rectangle
3x-4 (2x+2) = 6x^2-8x+6x-8
=6x^2-2x-8 = 3x^2-x-4
Small rectangle
(X-3) (x-6) = x^2-3x-6x+18
=x^2-9x+18
Big-small= 2x^2+8x-22 is the area of the shaded region
