3 years ago

Answer, no explanation needed. Thanks.

Mathematics

1 answer:

chubhunter [2.5K]3 years ago

4 0

Answer:

$f(-2)=1\\\\f(-6)=-4\\\\f(2)=4\\\\f(-2)-f(2)=-3$

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Ira Lisetskai [31]

<u>Answer:</u>

The correct answer option is c. $\frac{1}{9a^2}$ .

<u>Step-by-step explanation:</u>

We are given an expression $(27a^{-3})^{-\frac{2}{3} }$ and we are supposed to simplify it.

We can also write $(27a^{-3})^{-\frac{2}{3} }$ as $(\frac{3^3}{a^3} )^{-\frac{2}{3} }$ .

We know the power rule (a^m)^n=a^{mn} which means that to raise a power to a power you need to multiply the exponents.

So multiplying the exponents to get:

$\frac{3^{(3.-\frac{2}{3})} }{a^{(3.\frac{2}{3})} }\\\\\frac{3^{-2}}{a^2}\\ \\\frac{1}{3^2a^2} \\\\\frac{1}{9a^2}$

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Dovator [93]

18??
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3 years ago

Solve for the given variable 3(2x+5)=4x+21

Nookie1986 [14]

Answer:

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Step-by-step explanation:

3(2x+5)=4x+21

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2x+15= 21

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