if a rectangle is twice as long as it wide and has a perimeter of 48 inches, what is the area of the rectangle
1 answer:
Answer: 128
Step-by-step explanation:
Let the width be W then the length will be 2W since it is twice as long as it width.
The formula for calculating the perimeter of a rectangle is given by :
P = 2 ( L + W )
48 = 2 ( W + 2W )
48 = 2(3W)
48 = 6W
Divide through by 6
Therefore:
W = 48/6
W = 8 inches
This means that the Length is 2 x 8 = 16 inches
Area = Length x breadth
Area = 16 x 8
Area = 128
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tan C=AB/BC==>BC=tan 49° * 250=287,59210... (feet)
sin C=AB/AC==>AC=250/sin 49°=331,253248... (feet)
tan C=AB/BC==>BC=tan 49° * 250=287,59210... (feet)
sin C=AB/AC==>AC=250/sin 49°=331,253248... (feet)