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zzz [600]
3 years ago
15

a can of paint will cover 20 square units my area that i want to paint has lenght of 20 inches and a width of 10 inches how many

cans of paint will i need to buy
Mathematics
2 answers:
tigry1 [53]3 years ago
7 0
You need to buy 10 cans of paint
Usimov [2.4K]3 years ago
5 0
You need to buy 8 cans of paint and shut up is a bad word
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The area is 5 cm^2 of the pyramid
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3 years ago
Please help!! 20 points! #18 a,b,c
AVprozaik [17]
A. 60 degrees
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=. What does the expression (x+3)(9) represent? Why?
tresset_1 [31]
Because when you multiply the 9 by x you get 9x and when you multiply the 9 by 3 you get 27. So then your final answer would be 9x + 27.
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6 0
1 year ago
Find the final value and the compound interest if $8000 is invested for 2 years at 27% p.a.
gladu [14]

Answer:

$8000 / 2 = $4000 x 27 = $108000

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8 0
2 years ago
The number of acres a farmer uses for planting pumpkins will be at least 2 times the number of acres for planting corn. The diff
jeka94

Answer:

Step-by-step explanation:

A) Let x represent acres of pumpkins, and y represent acres of corn. Here are the constraints:

  x ≥ 2y . . . . . pumpkin acres are at least twice corn acres

  x - y ≤ 10 . . . . the difference in acreage will not exceed 10

  12 ≤ x ≤ 18 . . . . pumpkin acres will be between 12 and 18

  0 ≤ y . . . . . the number of corn acres is non-negative

__

B) If we assume the objective is to maximize profit, the profit function we want to maximize is ...

  P = 360x +225y

__

C) see below for a graph

__

D) The profit for an acre of pumpkins is the highest, so the farmer should maximize that acreage. The constraint on the number of acres of pumpkins comes from the requirement that it not exceed 18 acres. Then additional profit is maximized by maximizing acres of corn, which can be at most half the number of acres of pumpkins, hence 9 acres.

So profit is maximized for 18 acres of pumpkins and 9 acres of corn.

Maximum profit is $360·18 +$225·9 = $8505.

7 0
3 years ago
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