8. Find the measure of BAC. The figure is not drawn to sale. (1 point)

Mathematics

1 answer:

Sphinxa [80]2 years ago

7 0

57 degrees is the answer

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Help with this question please and thank :>

Illusion [34]

Answer:

13.858

Step-by-step explanation:

The steps are listed in the graphic.

4 0

2 years ago

A right triangular prism has a height of 3 ft, a width of 4 ft, and a hypotenuse of 5 ft. The depth of the triangle is missing.

DiKsa [7]

Depth=15
x=(height(h)*width(w)*hypotenuse(y))/2
x=(3*4*5)/2=(60/2)=30
y=(x(x-h)(x-w)(x-y))^(1/2)
f=(-h^4+2(hw)^2+2(wy)^2-w^4+2(hy)^2-y^4)^(1/2)
f=(-3^4+2(3*4)^2+2(4*5)^2-4^4+2(3*5)^2-5^4)^(1/2)
f=576^(1/2)
f=24
Surface Area= 2f(.5)+(h+w+y)*depth
192=depth*(3+4+5)+24(.5)
180=(3+4+5)*depth
180=(12)(depth)
15=depth

8 0

3 years ago

HELPPPPPP IMMA FAIL!! PLSSSSSS!!

vredina [299]

Answer:

59049

Step-by-step explanation:

5 0

2 years ago

6. Write the explicit formula for the geometric sequence of the height of the ball on the 10th bounce.First bounce: 54 inchescom

Nat2105 [25]

The height of the ball initially is 54 inches. The common ratio has been provided which is 0.750.

The explicit formular for the geometric sequence is shown as;

$\begin{gathered} ar^{n-1} \\ \text{Where a is the first term in the sequence,} \\ r\text{ is the common ratio betw}een\text{ every successive term} \\ \text{And n is the nth term} \\ \text{The explicit formular for the height of the ball on the 10th bounce is;} \\ ar^{n-1} \\ 54\times(0.750)^{10-1} \\ 54\times(0.750)^9 \\ 54\times0.07508468\ldots \\ 4.0545 \end{gathered}$

The explicit formula is shown as;

54 x (0.750)^9

The rest is simply to solve for the height on the 10th bounce

5 0

8 months ago

1.Given the function h(t) = t³ - 2t, find h(-5).

Svetllana [295]

Answer:

-65

Step-by-step explanation:

h(t) = (-5)^3 -2(-5)

h(t) = -75 +10

h(t) = -65

7 0

1 year ago