Question

(2x-6) times (3x^2-4x-5)

Answer 1

For this case we must multiply the following expression:

$(2x-6) (3x ^ 2-4x-5)$

Applying distributive property we have:

$(2x) (3x ^ 2) - (2x) (4x) - (2x) (5) - (6) (3x ^ 2) + (6) (4x) + (6) (5) =$

By definition of multiplication of powers of the same base, we have to put the same base and add the exponents:

$6x ^ 3-8x ^ 2-10x-18x ^ 2 + 24x + 30 =$

Adding similar terms:

$6x ^ 3-26x ^ 2 + 14x + 30$

Answer:

$6x ^ 3-26x ^ 2 + 14x + 30$