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ivanzaharov [21]
3 years ago
7

The last answer is highlighted becausese its wrong. Please help me

Mathematics
1 answer:
LenaWriter [7]3 years ago
8 0
Multiplication Property of Equality: They multiplied both sides by 5/3 to isolate x on the left

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Please find the angle measurements u would be tha goat
nikitadnepr [17]

HXE=133

HXB=70

CXD=43

DXE=47

FXD=70

4 0
4 years ago
Plz answer this within 2 mins and receive brainiest......
In-s [12.5K]

Answer:

Brand B is cheaper by 0.17 per pound.

Step-by-step explanation:

Brand A = 47.7/45 = 1.06

Brand B = 48.95/55 = 0.89

3 0
3 years ago
Read 2 more answers
ANSWER QUICK PLEASE!!
Kazeer [188]
First you can solve for angle C because angles C and D are vertical and therefore congruent
So we do: 62+44+x=180 and solve
106+x=180
x=74
So then we know that angles C and D are 74 degrees 

Then we can solve for angle F:
x+74+50=180
Which can be rewritten as x=180-50-74

Hope this helps
5 0
3 years ago
Q1 : Find the inverse of the function.
Mamont248 [21]

Answer:

1. Option D is correct.

2. Option B is correct.

3. Option B is correct.

Step-by-step explanation:

Inverse function defined as the the function that undergoes the action of the other function.

A function f^{-1} is the inverse of f if whenever y =f(x) and x =f^{-1}

To find the inverse of the function:

Q1.

Given the function:  f(x) = 7x -1

Put y for f(x) and solve for x;

y= 7x -1

Add 1 both sides we get;

y + 1 = 7x

Divide both sides by 7 we get;

x = \frac{y+1}{7}

Put f^{-1}(y) for x;

f^{-1}(y) = \frac{y+1}{7}

Interchange y =x, we have

f^{-1}(x) = \frac{x+1}{7}

Q 2.

Given the function:

f(x) = x^3 - 7

Put y for f(x) and solve for x;

y = x^3-7

Add 7 both sides we get;

y + 7 =x^3

taking cube root both sides we get

x =\sqrt[3]{y+7}

Put f^{-1}(y) for x;

f^{-1}(y) =\sqrt[3]{y+7}

Interchange y =x, we have

f^{-1}(x) = \sqrt[3]{x+7}

Q3 .

Given the function:

f(x) = 5x^3 - 3

Put y for f(x) and solve for x;

y = 5x^3-3

Add 3 both sides we get;

y + 3 =5x^3

Divide both sides by 5 we get;

x^3 = \frac{y+3}{5}

taking cube root both sides we get

x = \sqrt[3]{\frac{y+3}{5} }

Put f^{-1}(y) for x;

f^{-1}(y) = \sqrt[3]{\frac{y+3}{5} }

Interchange y =x, we have

f^{-1}(x) = \sqrt[3]{\frac{x+3}{5} }




7 0
3 years ago
Segment AB has endpoints at (-3, 5) and (4, 0). Explain and demonstrate how to find the length of this: length of AB 74 In?
Alchen [17]

Answer:

12. 5

11.

10

10

15. 7

14. 11

2

=

16

16

18. 3

+

11

17

3

4

co

loo

8

Step-by-step explanation:

12. 5

11.

10

10

15. 7

14. 11

4 0
2 years ago
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