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timurjin [86]
3 years ago
15

A scale on a map shows that 2 inches = 25 miles

Mathematics
1 answer:
ycow [4]3 years ago
4 0
4.4 inches because once you add 2 and 2 you 50 then add ten and you get 60
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A man whose height is 2.1 m casts a shadow that is 3.2 m in length. What is the approximate height of a building that casts a sh
Colt1911 [192]

Answer:

ok so first

2.1 divided by 3.2 =0.65625

0.65625*11.5=7.546875

So the answer is B

Hope This Helps!!!

6 0
3 years ago
You have decided to hire your little brother to clean your room for the next month. as payment, you will give him 1 penny the fi
Dafna11 [192]
1, 2, 4, 8, 16 ...

a = 1

d = 8/4 = 2

Sn = n/2(2a + (n-1)d) = 30(2 + (29×2)) = 30(60) = 1800

Ans = $1,800 ...//
6 0
3 years ago
Please do correctly! I will mark you Brainliest!
kolbaska11 [484]

Answer:

3(4+√2)

Step-by-step explanation:

Here we need to find the perimeter of the given figure. Here the given figure is made from a triangle and a square. The side lenght of the square is 3. We need to find the hypontenuse of the triangle in order to find Perimeter .

<u>•</u><u> </u><u>Using</u><u> </u><u>Pyth</u><u>agoras</u><u> Theorem</u><u> </u><u>:</u><u>-</u><u> </u>

⇒ h² = p² + b²

⇒ h² = 3² + 3²

⇒ h² = 9 + 9

⇒ h² = 18

⇒ h = √[ 9 × 2 ]

⇒ h = 3√2 .

Therefore the perimeter will be ,

⇒ P = 3√2 + 3 + 3 + 3 + 3

⇒ P = 3√2 + 12

⇒ P = 3( 4 + √2)

<h3><u>Hence</u><u> </u><u>the</u><u> </u><u>perim</u><u>eter</u><u> of</u><u> the</u><u> </u><u>figure</u><u> </u><u>is</u><u> </u><u>3</u><u>(</u><u>4</u><u>+</u><u>√</u><u>2</u><u>)</u><u> </u><u>.</u></h3>

4 0
3 years ago
Haruka hiked several kilometers in the morning. She hiked only 6 kilometers in the afternoon, which was 25%, percent less than s
Semenov [28]

Answer:

14 km

Step-by-step explanation:

6 km in the afternoon

x km in the morning

6= x- 25%

6= 0.75x

x= 6/0.75

x= 8 km

total 6+8= 14 km

4 0
3 years ago
Part A: Solve A = (x + 23) for x. (4 points) Part B: Determine the value of x when A = 108. (2 points) Part C: Solve -np - 90 &g
Galina-37 [17]
<span>Part A: Solve A = (x + 23) for x.

A = x + 23

=> A - 23 = x + 23 - 23

=> A - 23 = x

=> x = A - 23 <------- answer

Part B: Determine the value of x when A = 108

Replace the value of A in the expression x = A - 23

x = 108 - 23 = 75

x = 75 <------- answer

Part C: Solve -np - 90 > 30 for n.

-np - 90 > 30

=> -np + np - 90 >30 +  np

=> - 90 > 30 + np

=> -90 - 30 > 30 - 30 + np

=> -120 > np

=> np < - 120 <----- answer
</span>
7 0
3 years ago
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