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4 years ago

Einstein showed that the photoelectric effect could be understood by:

1 answer:

3 0

Einstein showed how the photoelectric effect could be understood
by treating light as a stream of particles, with each particle's energy
depending on the color of the light.

Einstein is famous for his work in Relativity. But it was his explanation
of the photoelectric effect... now a pretty obscure topic ... that won him
his only Nobel Prize.

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An excited hydrogen atom releases an electromagnetic wave to return to its normal state. You use your futuristic dual electric/m

Norma-Jean [14]

Answer:

Explanation:

Direction of velocity of electromagnetic wave is given by the formula

E = E j ( vector form )

B = - Bi ( vector form )

Direction of velocity = direction of vector E X B

= E X B

= E j x -Bi

= - EB -k

v = EBk

So the direction of velocity will be along z direction.

6 0

4 years ago

A 65 kg students is walking on a slackline, a length of webbing stretched between two trees. the line stretches and sags so that

polet [3.4K]

Answer : Tension in the line = 936.7 N

Explanation :

It is given that,

Mass of student, m = 65 kg

The angle between slackline and horizontal, $\theta=20^0$

The two forces that acts are :

(i) Tension

(ii) Weight

So, from the figure it is clear that :

$mg=2T\ sin\ \theta$

$T=\dfrac{mg}{2\ sin\theta}$

$T=\dfrac{65\ kg\times 9.8\ m/s^2}{2(sin\ 20)}$

$T=936.7\ N$

Hence, this is the required solution.

5 0

3 years ago

Read 2 more answers

A battery of constant voltage is connected to a variable resistor. As the resistance of the resistor increases, what happens to

vova2212 [387]

The electric current amount will vary according to the resistance value when connected to a voltage of a power supply. If resistance is reduced, current will increase. So, if the resistance is infinite (open circuit), the current could be considered zero, or infinitesimal small, if the resistance is zero (of infinitesimal small), the current will tend to be the maximum the power supply can provide. Here is the case of the power supply capability, input resistance, capacity to hold and regulate the output voltage to a certain maximum current, etc. Normally when you short circuit (zero ohms resi

4 0

3 years ago

The normal force of a parked car is 15,000 Newtons. The coefficient of static friction between the rubber of the tires and the a

Shtirlitz [24]

Answer:

11250 N

Explanation:

From the question given above, the following data were obtained:

Normal force (R) = 15000 N

Coefficient of static friction (μ) = 0.75

Frictional force (F) =?

Friction and normal force are related by the following equation:

F = μR

Where:

F is the frictional force.

μ is the coefficient of static friction.

R is the normal force.

With the above formula, we can calculate the frictional force acting on the car as follow:

Normal force (R) = 15000 N

Coefficient of static friction (μ) = 0.75

Frictional force (F) =?

F = μR

F = 0.75 × 15000

F = 11250 N

Therefore, the frictional force acting on the car is 11250 N

3 0

3 years ago

At a local swimming pool, the diving board is elevated h = 9.5 m above the pool's surface and overhangs the pool edge by L = 2 m

eimsori [14]

Answer:

1) The time it takes the diver to move off the end of the diving board to the pool surface, $t_w$ , is approximately 1.392 seconds

2) The horizontal distance from the edge of the pool to where the diver enters the water, $d_w$ , is approximately 5.76 meters

Explanation:

1) The given parameters are;

The height of the diving board above the pool's surface, h = 9.5 m

The length by which the diving board over hangs the pool L = 2 m

The speed with which the diver runs horizontally along the diving board, v₀ = 2.7 m/s

Taking $t_w$ = The time it takes the diver to move off the end of the diving board to the pool surface

Therefore, we have from the equation of free fall;

h = 1/2 × g × $t_w$ ²

Where;

g = The acceleration due to gravity = 9.81 m/s²

Substituting the values, gives;

9.5 = 1/2 × 9.81 × $t_w$ ²

$t_w$ = √(9.5/(1/2 × 9.81)) ≈ 1.392 s

The time it takes the diver to move off the end of the diving board to the pool surface = $t_w$ ≈ 1.392 s

2) The horizontal distance, $d_w$ , in meters from the edge of the pool to where the diver enters the water is given as follows;

$d_w$ = L + v₀ × $t_w$ = 2 + 2.7× 1.392 ≈ 5.76 m

∴ The horizontal distance from the edge of the pool to where the diver enters the water ≈ 5.76 meters.

7 0

3 years ago