An object of mass 25 kg acted upon by a net force of 10 N will experience an acceleration of?
1 answer:
You might be interested in
Answer: 6.24 km
Explanation:
Given
The magnitude of the first vector(say)
the magnitude of the second vector(say)
the angle between them is
The resultant vector magnitude is given by
(a) 392 N/m
Hook's law states that:
(1)
where
F is the force exerted on the spring
k is the spring constant
is the stretching/compression of the spring
In this problem:
- The force exerted on the spring is equal to the weight of the block attached to the spring:
- The stretching of the spring is
Solving eq.(1) for k, we find the spring constant:
(b) 17.5 cm
If a block of m = 3.0 kg is attached to the spring, the new force applied is
And so, the stretch of the spring is
And since the initial lenght of the spring is
The final length will be