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babunello [35]
3 years ago
9

An object of mass 25 kg acted upon by a net force of 10 N will experience an acceleration of?

Physics
1 answer:
Zolol [24]3 years ago
6 0

Answer:

0.4 m/s2

Explanation:

mass: 25kg

net force: 10 N

acceleration: ?

net force ÷ by mass= acceleration

10 N ÷ 25 Kg = 0.4 m/s2

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A 0.50-kg ball, attached to the end of a horizontal cord, is rotated in a circle of radius 1.9 m on a frictionless horizontal su
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Answer:

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Explanation:

The ball is moving in a circle, so the force is centripetal.

One formula for calculating centripetal force is:

F_c= \frac{mv^2}r}

The mass of the ball is 0.5 kilograms. The radius is 1.9 meters. The centripetal force is 85 Newtons or 85 kg*m/s².

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Substitute the values into the formula.

85 \ kg*m/s^2 = \frac{0.5 \ kg *v^2}{1.9 \ m}

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(1.9 \ m)(85 \ kg*m/s^2) = \frac{0.5 \ kg *v^2}{1.9 \ m}*1.9 \ m

(1.9 \ m)(85 \ kg*m/s^2) = {0.5 \ kg *v^2}

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\frac {161.5 \ kg*m^2/s^2}{0.5 \ kg} = \frac{0.5 \ kg*v^2}{0.5 \ kg}

\frac {161.5 \ kg*m^2/s^2}{0.5 \ kg} =v^2

323 \ m^2/s^2 = v^2

Take the square root of both sides of the equation.

\sqrt {323 \ m^2/s^2} =\sqrt{ v^2

\sqrt {323 \ m^2/s^2} =v

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The original measurements have 2 significant figures, so our answer must have the same.

For the number we found, 2 sig fig is the ones place. The 9 in the tenth place tells us to round the 7 to an 8.

18 \ m/s =v

The maximum speed is approximately <u>18 meters per second.</u>

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In this case, all measures have the same number of significant figures: two. so we calculate the product, and then limit the answer value to exactly two significant figures:

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so we have

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