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babunello [35]
3 years ago
9

An object of mass 25 kg acted upon by a net force of 10 N will experience an acceleration of?

Physics
1 answer:
Zolol [24]3 years ago
6 0

Answer:

0.4 m/s2

Explanation:

mass: 25kg

net force: 10 N

acceleration: ?

net force ÷ by mass= acceleration

10 N ÷ 25 Kg = 0.4 m/s2

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how much energy is required to move a 4.00-microcoulomb charge through a potential difference of 36.0 volts?
musickatia [10]

Answer:

All you gotta do is search it up. ask the same question you asked on here, type it into google, it'll teach you a lot more than your actual teachers.

Explanation:

4 0
3 years ago
Richard is driving home to visit his parents. 150 mi of the trip are on the interstate highway where the speed limit is 65 mph .
Serggg [28]

Answer:

t = 25.5 min

Explanation:

To know how many minutes does Richard save, you first calculate the time that Richard takes with both velocities v1 = 65mph and v2 = 80mph.

t_1=\frac{x}{v_1}=\frac{150mi}{65mph}=2.30h\\\\t_2=\frac{x}{v_2}=\frac{150mi}{80mph}=1.875h

Next, you calculate the difference between both times t1 and t2:

\Delta t=t_1-t_2=2.30h-1.875h=0.425h

This is the time that Richard saves when he drives with a speed of 80mph. Finally, you convert the result to minutes:

0.425h*\frac{60min}{1h}=25.5min=25\ min\ \ 30 s

hence, Richard saves 25.5 min (25 min and 30 s) when he drives with a speed of 80mph

3 0
3 years ago
And explosion occur 17 km away the time it takes for it sound to reach your ears traveling at 340 m/s is
Mrrafil [7]

Answer:

<h3>t = 100secs</h3>

Explanation:

The following data

Distance x = 17km = 17000m

Speed v = 340m/s

Using the formula to get the time;

2x = vt

t = 2x/v

t = 2(17000)/340

t = 34000/340

t = 100secs

<em>Hence it takes 100seconds for the sound to reach your ears</em>

6 0
3 years ago
8. What is the frequency heard by a person driving at 18 m/s toward a blowing factory whistle (600 Hz) if
Angelina_Jolie [31]

Answer:

631.7 Hz

Explanation:

The Doppler effect is a phenomenon that occurs when there is relative motion between an observer and a source of a wave. When this occurs, the is a change in the apparent frequency of the wave, as observed by the observer.

In particular, the new apparent frequency can be calculated as:

f'=\frac{v\pm v_o}{v\pm v_s}f

where

f is the real frequency

f' is the apparent frequency

v is the speed of the wave

v_o is the velocity of the observer (positive if the observer is moving towards the source, negative if moving away)

v_s is the velocity of the source (negative if the source is moving towards the observer, positive if moving away)

In this problem:

v = 340.6 m/s is the speed of the sound wave

f = 600 Hz is the real frequency of the sound

v_o = +18 m/s is the velocity of the person

v_s=0 is the velocity of the source

Substituting, we find:

f'=\frac{340.6+18}{340.6}(600)=631.7 Hz

7 0
3 years ago
If the frequency of an electromagnetic wave is reduced to one third, what happens to the wavelength?
Olin [163]
As the frequency slows down, the wavelength increases.
7 0
3 years ago
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