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3 years ago

How do atoms relate to the periodic table?

Physics

2 answers:

oksian1 [2.3K]3 years ago

5 0

Answer:

The organization of electrons in atoms explains not only the shape of the periodic table but also the fact that elements in the same column of the periodic table have similar chemistry. The same concept applies to the other columns of the periodic table.

guapka [62]3 years ago

4 0

The properties of an atom relate directly to the number of electrons in various orbitals, and the periodic table is much like a road map among those orbitals such that chemical properties can be deduced by the position of an element on the table.

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What happens to kinetic energy of a snowball as it rolls across the lawn and gains mass

Naya [18.7K]

If an object whose mass is growing keeps the same, unchanged
kinetic energy, then its motion must slow down, because

Kinetic Energy = (1/2) (mass) (speed)² .

3 0

4 years ago

Read 2 more answers

I shared a picture of the problem. It’s a basic Physics question and an Algebra question.

julia-pushkina [17]

Hence the expression of ω in terms of m and k is

$\omega = \sqrt{\frac{k}{m}$

Given the expressions;

$T_s = 2 \pi \sqrt{\frac{m}{k} } \ and \ T_s = \frac{2 \pi}{\omega}$

Equating both expressions we will have;

$2 \pi \sqrt{\frac{m}{k} } = \frac{2 \pi}{\omega}$

Divide both equations by 2π

$\frac{2 \pi\sqrt{\frac{m}{2 \pi} } }{2 \pi}=\frac{\frac{2 \pi}{\omega} }{2\pi}\\\sqrt{\frac{m}{2 \pi} } = \frac{1}{\omega}\\$

Square both sides

$(\sqrt{\frac{m}{k} } )^2 = (\frac{1}{\omega} )^2\\\frac{m}{k} = \frac{1}{\omega ^2} \\\omega ^2 = \frac{k}{m}$

Take the square root of both sides

$\sqrt{\omega ^2} =\sqrt{\frac{k}{m} } \\\omega = \sqrt{\frac{k}{m}$

Hence the expression of ω in terms of m and k is

$\omega = \sqrt{\frac{k}{m}$

3 0

3 years ago

An apple has a mass of 0.136kg and a watermelon has a mass of 9.07kg. Work out the mass of the apple as a percentage of the mass

Galina-37 [17]

7 the answer is 7 JK

3 0

3 years ago

What two products are formed from the fission of uranium?

zheka24 [161]

Fragments and gamma<span> rays</span>

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3 years ago

Steam at 0.6 mpa, 200 oc, enters an insulated nozzle with a velocity of 50 m/s. It leaves at a pressure of 0.15 mpa and a veloci

vladimir1956 [14]

Answer:

x2 = 0.99

Explanation:

from superheated water table

at pressure p1 = 0.6MPa and

temperature 200 degree celcius

h1 = 2850.6 kJ/kg

From energy equation we have following relation

$\dot m(h1 + \frac{v1^2}{2} +gz1) + Q = \dot m(h2 + \frac{v2^2}{2} +gz1) + W$

$\dot m(h1 + \frac{v1^2}{2} = \dot m(h2 + \frac{v2^2}{2}$

$(h1 + \frac{v1^2}{2} = (h2 + \frac{v2^2}{2}[tex]2850.6 + \frac{50^2}{2} *\frac{1 kJ/kg}{1000 m^2/s^2} = h2 + \frac{600^2}{2} *\frac{1 kJ/kg}{1000 m^2/s^2}$

h2 = 2671.85 kJ/kg

from superheated water table

at pressure p2 = 0.15MPa

specific enthalpy of fluid hf = 467.13 kJ/kg

enthalpy change hfg = 2226.0 kJ/kg

specific enthalpy of the saturated gas hg = 2693.1 kJ/kg

as it can be seen from above value hf>h2>hg, so phase 2 is two phase region. so we have

quality of steam x2

h2 = hf + x2(hfg)

2671.85 = 467.13 +x2*2226.0

x2 = 0.99

5 0

3 years ago