Answer:
Nucellus makes the most of the ovule. It encloses the embryo sac. They have abundant food reserves and therefore act as nutritive tissues for the embryo in some plants.
It moves by active transport.hope this helps!
Answer:
K+-coupled.
Explanation:
The transport of the solutes may occur along the concentration gradient or against the concentration gradient. Two main types of transport that occur in living organism are active process and passive process.
The passive transport do not require the energy for its transport whereas the active transport require energy. The K+ coupled transport do not require any energy molecule for its transport and easily transfer by the leaky channel. Hence, the K+-coupled transport is not the common active transport.
Thus, the correct answer is option (C).
<span>There are many differences between these groups. Including the sporangia size and structure, type of spores produced, structure of the gametophyte generations, the way each generation lives, some are parasitic some aren't, the habitat. etc. It would require a detailed list of information. Try looking up basic characteristics of each group and making a table to compare them to the ferns. You could use: sporangia, gametes, sporophyte appearance, habitat etc.
They are all vascular by the way, including ferns. The familiar mosses are not, they are Bryophyes which you have not asked about. The club mosses for example are Lycophytes, and very dissimilar to familiar moss.</span><span>
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Answer:
C. "Because you have had one child with Tay-Sachs, you must each carry the allele. Any child you have has a 25% chance of having the disease
Explanation:
Tay-Sachs disease is an autosomal recessive disorder that means a child will acquire the phenotype or we can say disease only when both the alleles which cause disease are present in the child.
Here, in this condition neither parent has Tay-Sachs but they gave birth to a child who is suffering from the disease then it simply means that both the parents are carrier of this disease i.e. they both are heterozygous.
The cross and probability of healthy and diseased child is shown as under:
Mother Father
Parents Tt Tt
/ | | \
Off-springs TT Tt Tt tt
<u>Out of these 4 probable off-springs only 3 with genotype TT, Tt & Tt will be healthy while the 1 with genotype tt will be diseased.</u><u> </u><u>So, the probability of diseased child is 1/4 which is 25%. </u>
Also, the birth of children is an independent event so if one child has already been born with this disease then it doesn't mean that the next 3 children will be healthy for sure i.e. birth of first child cannot influence the next child. In short we can also say that in the next birth, there is still 25% chance of the child being born with this disease because previous birth has nothing to do with next birth.
