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mina [271]
3 years ago
14

How do I write 125% in simplest form

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
7 0

Answer:

The answer is 5/4 in fraction form and 1.25 decimal form


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-5
Tresset [83]
Can you please take a picture of the question? if you do i’ll help you, i just don’t understand what this is asking.
3 0
4 years ago
Will give brainliest! Ignore the other question on the top but can u ansawer all of them, il know if your putting random letters
Zina [86]

Answer:

6: S

7: C

8: C

9: C

10: N

11: C

12: S

13: S

14: N

15: C

Step-by-step explanation:

Complementary angles add to 90 degrees.

Suplementary angles add to 180 degrees.

6 0
4 years ago
Write the ratio as a fraction in simplest form, with whole numbers in the numerator and denominator.
Anit [1.1K]

Answer:

8/9

Step-by-step explanation:

8 0
4 years ago
(X^2+x-6)(2x^2+4x) factor completely
MissTica

Answer:

2x\left(x-2\right)\left(x+3\right)\left(x+2\right)

Step-by-step explanation:

Lets go ahead and take a step by step approach to solving your problem.

First we must start by factoring x^2+x-6.

To do this, we must break the expression into groups! Although I will also provide a definition to help you understand! For ax^2+bx+c we need to find u, v > u\cdot \:v=a\cdot \:c and u+v=b which we will group into \left(ax^2+ux\right)+\left(vx+c\right).

The values we have are...a=1,\:b=1,\:c=-6 and u\cdot v=-6,\:u+v=1.

Now we need the factors of 6 which are 1, 2, 3 and 6. We also need the negative factors which you get simply by multiplying the positives by -1 or just reversing them.

Now we need to check for every two factors if u + v = 1.

\mathrm{Check}\:u=1,\:v=-6: \:u\cdot v=-6,\:u+v=-5 \Rightarrow  \mathrm{False}

\mathrm{Check}\:u=2,\:v=-3: \:u\cdot v=-6,\:u+v=-1 \Rightarrow  \mathrm{False}

\mathrm{Check}\:u=3,\:v=-2: \:u\cdot v=-6,\:u+v=1 \Rightarrow  \mathrm{True}

\mathrm{Check}\:u=6,\:v=-1: \:u\cdot v=-6,\:u+v=5 \Rightarrow  \mathrm{False}

Therefore u=3,\:v=-2.

Now we want to \mathrm{Group\:into\:}\left(ax^2+ux\right)+\left(vx+c\right). Which is \left(x^2-2x\right)+\left(3x-6\right).

Now we must factor x from x^2-2x.

Lets apply the exponent rule of a^{b+c}=a^ba^c which means x^2=xx.

Therefore we now have xx - 2x. Lets factor out the common term of x to get x(x - 2).

Now factor 3 out of 3x-6.

Rewrite 6 as 3 * 2. 3x-3\cdot \:2.

Now factor out the common term of 3 > 3\left(x-2\right).

x\left(x-2\right)+3\left(x-2\right) > Factor out the common term of x - 2 > \left(x-2\right)\left(x+3\right).

Now lets factor 2x^2+4x.

Apply the previous exponent rule of a^{b+c}=a^ba^c > x^2=xx > 2xx+4x.

Now rewrite 4 as 2 * 2 > 2xx+2\cdot \:2x.

Now factor out the common term of 2x to get 2x(x + 2).

Combine it all and we get 2x\left(x-2\right)\left(x+3\right)\left(x+2\right).

Hope this helps!

7 0
3 years ago
Write the equation of a line parallel to the line y = 2x that passes through -2,-1
maksim [4K]

Answer:

y = 2x + 3

Step-by-step explanation:

A line parallel to y = 2x has exactly the same slope but a different y-intercept, b.

Start with y = mx + b, and replace m with 2, y with -1 and x with -2:

-1 = 2(-2) + b, or

-1 = -4 + b.

Then b = 3, and the desired equation is y = 2x + 3

7 0
3 years ago
Read 2 more answers
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