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Rzqust [24]
3 years ago
14

Evaluate 5p to the power of 3 when p = -2

Mathematics
2 answers:
Mrac [35]3 years ago
7 0
5(-2)^3 5(-2) is -10 to the power of 3 is -1000
kumpel [21]3 years ago
5 0
5(p)^-2

5(-2)^3

5(-8)

-40
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HELP NEEDED ASAP! Thanks :)
Arlecino [84]

Answer:

3

Step-by-step explanation:

First we must find the total boxes of pens

15 + 9 = 24

Then we can divide the total cost by the total number of boxes of pens

$72 / 24 boxes = 3

4 0
2 years ago
What is the answer to my question, 45x27?​
TiliK225 [7]

Answer:

1,215

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Como puedo poner 2 3/5 en decimal​
Alex73 [517]

When turning a fraction into a decimal, any whole numbers comes before the "." and the fraction will become after the ".".

To make it simple, turn the fraction into a "over 100" fraction to make it easier.

Multiple both numeriator and denominator by a specific number, to turn the denominator into a 100. You must times the numeriator as well since your changing the denominator.

100 / 5 = 20

So now, multiple both sides of the fraction by 20.

3 x 20 = 60

5 x 20 = 100

2 60/100

Now, put the whole number in front of the decimal symbol.

2.___

Now, take the numeriator and put it behind the decimal symbol.

2.60

So, when turning 2 3/5 into a decimal, it is 2.60.

8 0
3 years ago
What is the avarege of -2.5,5.2,1.7 and -0.8
aleksandr82 [10.1K]

Average:

4.4 / 3 = 1.4666666666667

Count:

3

Sum:

4.4

Average:

4.4 / 3 = 1.4666666666667

Count:

3

Sum:

4.4

5 0
3 years ago
Madison works as a salesperson at an electronics store and sells phones and phone accessories, and makes a fixed commission for
Jet001 [13]

Answer:

Price of each phone: \$9

Price of each accessory: \$3.5

Step-by-step explanation:

Let be "p" the  price in dollars of each phone and "a" the price in dollars of each accessory.

Set up a system of equations:

\left \{ {{8p+10a=107} \atop {4p+23a=116.50}} \right.

You can use the Elimination Method to solve the system.

Multiply the second equation by -2 and add both equations:

\left \{ {{8p+10a=107} \atop {-8p-46a=-233}} \right.\\............................\\-36a=-126\\\\a=\frac{-126}{-36}\\\\a=3.5

Substitute the value of "a" into the first equation and solve for "p":

8p+10(3.5)=107\\\\8p=107-35\\\\p=\frac{72}{8}\\\\p=9

4 0
3 years ago
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